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3 years ago

Define Aqua regia and write a short note on it

Chemistry

1 answer:

meriva3 years ago

3 0

Answer:

Explanation:

Aqua regia is a strong and very concentrated acid formed by mixing Hydrochloric acid(HCl) and nitric acid.

The acid is very corrosive due to its formulation and it nearly reacts to dissolve all substances including the unreactive gold metal. It is formed by mixing the two acids in a proportion of 1:3, i.e HCl in 3 parts and nitric acid in 1 part.

The mixture dissolves a wide range of metals

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PLEASE HELP ME STRAIGHT AWAY

san4es73 [151]

Desert plants commonly have small wax coated leaves to prevent moisture and water from evaporating. It is an important feature in desert plants to adapt to the arid climate. The wax on the leaves also protect the leaves from the chilling temperature of the desert at night.

4 0

2 years ago

In Part III, the phenolphthalein indicator is used to monitor the equilibrium shifts of the ammonia/ammonium ion system. The phe

AnnZ [28]

The pink color in the solution fades. Some of the colored indicator ion converts to the colorless indicator molecule.

<h3>Explanation</h3>

What's the initial color of the solution?

$\text{NH}_4\text{Cl}$ is a salt soluble in water. $\text{NH}_4\text{Cl}$ dissociates into ions completely when dissolved.

$\text{NH}_4\text{Cl} \; (aq)\to {\text{NH}_4}^{+} \; (aq) +{\text{Cl}}^{-} \; (aq)$ .

The first test tube used to contain $\text{NH}_4\text{OH}$ . $\text{NH}_4\text{OH}$ is a weak base that dissociates partially in water.

$\text{NH}_4\text{OH} \; (aq) \rightleftharpoons {\text{NH}_4}^{+} \;(aq)+ {\text{OH}}^{-} \; (aq)$ .

There's also an equilibrium between $\text{OH}^{-}$ and ${\text{H}_3\text{O}}^{+}$ ions.

${\text{OH}}^{-}\;(aq) + {\text{H}_3\text{O}}^{+} \;(aq) \to 2\; \text{H}_2\text{O} \;(l)$ .

$\text{OH}^{-}$ ions from $\text{NH}_4\text{OH}$ will shift the equilibrium between $\text{OH}^{-}$ and ${\text{H}_3\text{O}}^{+}$ to the right and reduce the amount of ${\text{H}_3\text{O}}^{+}$ in the solution.

The indicator equilibrium will shift to the right to produce more ${\text{H}_3\text{O}}^{+}$ ions along with the colored indicator ions. The solution will show a pink color.

What's the color of the solution after adding NH₄Cl?

Adding $\text{NH}_4\text{Cl}$ will add to the concentration of ${\text{NH}_4}^{+}$ ions in the solution. Some of the ${\text{NH}_4}^{+}$ ions will combine with $\text{OH}^{-}$ ions to produce $\text{NH}_4\text{OH}$ .

The equilibrium between $\text{OH}^{-}$ and ${\text{H}_3\text{O}}^{+}$ ions will shift to the left to produce more of both ions.

${\text{OH}}^{-}\;(aq) + {\text{H}_3\text{O}}^{+} \;(aq) \to 2\; \text{H}_2\text{O} \;(l)$

The indicator equilibrium will shift to the left as the concentration of ${\text{H}_3\text{O}}^{+}$ increases. There will be less colored ions and more colorless molecules in the test tube. The pink color will fade.

7 0

3 years ago

List a possible set of four quantum numbers (n,l,ml,ms) in order, for the highest energy electron in gallium?

Elena-2011 [213]

Gallum: Z = 31

electron configuration: [Ar] 4s^2 3d10 4s2 4p1

Highest energy electron: 4p1

Quantum numbers:

n = 4, because it is the shell number
l = 1, it corresponds to type p orbital
ml = may be -1, or 0, or +1, depending on space orientation, they correspond to px, py, pz
ms = may be -1/2 or +1/2, this is the spin number.

7 0

2 years ago

Methane gas reacts with oxygen in a gas stove.

nekit [7.7K]

Hey there!

CH₄ + 2O₂ → CO₂ + 2H₂O

carbon dioxide: product

methane: reactant

oxygen: reactant

water: product

Methane and oxygen are reactants because they are the substances we start with. They are on the side of the equation that the arrow is pointing away from.

Carbon dioxide and water are products because they are the new substances that are the yields of the equation. They are on the side of the equation that the arrow is pointing towards.

Hope this helps!

7 0

2 years ago

Predict the effect of adding a non competitive inhibitor to the reaction mixture on the rate of reaction at a high substrate con

Darya [45]

Answer:

A noncompetitive inhibitor can only bind to an enzyme with or without a substrate at several places at a particular point in time

Explanation:

this is because It changes the conformation of an enzyme as well as its active site, which makes the substrate unable to bind to the enzyme effectively so that the efficiency of the enzyme decreases. A noncompetitive inhibitor binds to the enzyme away from the active site, altering/distorting the shape of the enzyme so that even if the substrate can bind, the active site functions less effectively and most of the time also the inhibitor is reversible

8 0

3 years ago