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Alona [7]
3 years ago
12

15. What type of energy changes the physical states of matter?

Chemistry
1 answer:
maks197457 [2]3 years ago
7 0

Answer:

your answer will be option d hope ur help

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when 2.4 g zinc is added to hydrochloric acid, 450 ml of hydrogen gas form at a temperature of 32 C what is the pressure of the
Dovator [93]
First we need to find the number of moles of hydrogen gas formed
Zn + 2HCl ---> ZnCl₂ + H₂
stoichiometry of Zn to H₂ is 1:1
the number of Zn moles reacted - 2.4 g / 65.4 g/mol = 0.0367 mol
assuming Zn to be the limiting reactant 
number of Zn moles reacted = number of H₂ moles formed 
therefore number of H₂ moles formed = 0.0367 mol

we can use ideal gas law equation to find the pressure
PV = nRT
P - pressure
V - Volume - 450 x 10⁻⁶ m³
n - number of moles - 0.0367 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 32 °C + 273 = 305 K
substituting these values in the equation 
P x 450 x 10⁻⁶ m³ = 0.0367 mol x 8.314 Jmol⁻¹K⁻¹ x 305 K
P = 206.8 kPa 
pressure is 206.8 kPa
6 0
3 years ago
Why are protons in an atom so important? Question 5 options: A. Protons determine the atoms' identity (type of element) and wher
Gennadij [26K]

Your answer is A my friend as the atomic number of an atom is determined by the number of protons

4 0
3 years ago
Read 2 more answers
How to convert liters into milileters
Nutka1998 [239]
1 liter = 1,000 milliliters
8 0
3 years ago
What is metal and non metal
Umnica [9.8K]

Answer:

Metals are good conductors of heat and electricity, and are malleable (they can be hammered into sheets) and ductile (they can be drawn into wire).  Most of the metals are solids at room temperature, with a characteristic silvery shine (except for mercury, which is a liquid).  Nonmetals are (usually) poor conductors of heat and electricity, and are not malleable or ductile; many of the elemental nonmetals are gases at room temperature, while others are liquids and others are solids.  

Explanation:

7 0
3 years ago
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At 311 K, this reaction has a K c value of 0.0111 . X ( g ) + 2 Y ( g ) − ⇀ ↽ − 2 Z ( g ) Calculate K p at 311 K. Note that the
Aleks [24]

Answer:

K_{p}=4.35\times 10^{-4}

Explanation:

We know, K_{p}=K_{c}(RT)^{\Delta n}

where, R = 0.0821 L.atm/(mol.K), T is temperature in kelvin and \Delta n is difference in sum of stoichiometric coefficient of products and reactants

Here \Delta n=(2)-(2+1)=-1 and T = 311 K

So, K_{p}=(0.0111)\times [(0.0821L.atm.mol^{-1}.K^{-1})\times 311K]^{-1}=4.35\times 10^{-4}

Hence value of equilibrium constant in terms of partial pressure (K_{p}) is 4.35\times 10^{-4}

4 0
3 years ago
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