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3 years ago

Which two transitions can magma undergo?

Chemistry

2 answers:

UNO [17]3 years ago

6 0

Crystallization above the ground and crystallization below the ground

timofeeve [1]3 years ago

5 0

Answer:

Magma undergo two transitions:

Crystallization below the earth's surface.

Crystallization at the earth's surface

Explanation:

Magma undergo two transitions and forms igneous rocks.

Magma cools and crystallizes below the earth's surface to form intrusive igneous rock.

examples are granite and Diorite.

Magma cools and crystallizes above the earth's surface to form extrusive igneous rocks.

Examples are basalt and andesite.

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A gaseous hydrogen and carbon containing compound is decomposed and formed to contain 82.66% carbon and 17.34% hydrogen by mass.

Romashka [77]

Explanation:

Mole percentage of carbon = $\frac{percentage given}{molar mass of carbon}$

= $\frac{82.66}{12}$

= 6.89

Mole percentage of hydrogen = $\frac{percentage given}{molar mass of hydrogen}$

= $\frac{17.34}{1}$

= 17.34

Now, dividing mole percentage of both the atoms by 6.89.

Then, C = 1 and H = $\frac{17.34}{6.89}$ = 2.5

Hence, empirical formula is $C_{2}H_{5}$ .

As, it is given that P = 556 mm Hg. Convert mm Hg into atm as follows.

$\frac{556 mm Hg \times atm}{760 mm Hg}$

= 0.7316 atm

Volume is given as 158 mL. So, in liter volume is $\frac{158}{1000}$ equals 0.158 L.

According to ideal gas equation, PV = nRT

$0.7316 atm \times 0.158 L = \frac{mass}{molar mass} \times 0.082 atm L/mol K \times 298 K$

$0.7316 atm \times 0.158 L = \frac{0.275 g}{molar mass} \times 0.082 atm L/mol K \times 298 K$

molar mass = 58.2 g

Hence, molecular weight of $C_{2}H_{5}$ is $12 \times 2 + 5$ = 29.

Therefore, $(C_{2}H_{5})_{n}$ = 58

29 × n = 58

n = 2

Thus, molecular formula of the compound is $C_{4}H_{10}$ .

8 0

4 years ago

The closest star to our Sun is Proxima

lana [24]

answer:

not positive if this is correct just what i ould find on google

5 0

3 years ago

In the following reaction, how many liters of carbon dioxide will be produced if 250 liters of oxygen is used in the combustion

love history [14]

The balanced reaction would be:

C12H22O11 + 12O2 = 12CO2 + 11H2O

We are given the amount of oxygen used in the combustion. This will be the starting point of our calculation. We use the ideal gas equation to find for the number of moles.

n = PV / RT = 1.00(250 L) / (0.08206 atm L/mol K ) 273 K
n= 11.16 mol O2

11.16 mol O2 (12 mol CO2 / 12 mol O2) = 11.16 mol CO2

V = nRT/P =11.16 mol CO2 x 273 K x 0.08206 atm L/mol K / 1 atm
V=250 L

7 0

4 years ago

PLEASE HELP(2 questions)!!!!! BRAINLIEST IF FIRST AND CORRECTLY ANSWERED!!!

professor190 [17]

D
B
those are the correct answers

8 0

3 years ago

Myoclonus of the stapedial tendon or tensor tympani.

katen-ka-za [31]

Answer:

Tensor tympani syndrome

Explanation:

5 0

2 years ago