Question

The function f(x) = 1/2 x + 3/2 is used to complete this table.

Answer 1

Answer:

a) f(-1/2)  = -2 is NOT TRUE.

b)  f(0)  =3/2 is  TRUE.

c)   f(1)  = -1 is NOT TRUE.

d)   f(2)  = 1 is NOT TRUE.

e)   f(4)  = 7/2  is  TRUE.

Step-by-step explanation:

Here, the given function is  $f(x) = (\frac{1}{2}) x+\frac{3}{2}$

Now, checking for each values for the given function:

a) Putting x  = (-1/2):

 $f(\frac{-1}{2} ) = (\frac{1}{2})(\frac{-1}{2} ) +\frac{3}{2} = \frac{-1}{4} + (\frac{3}{2} )\\\implies f(x) = \frac{-1 + 6}{4} = (\frac{5}{4} )$

and (5/4) ≠  -2

Hence, f(-1/2)  = -2 is NOT TRUE.

b)Putting x  = 0 :

$f(0) = (\frac{1}{2})(0 ) +\frac{3}{2} = (\frac{3}{2} )$

Hence, f(0)  =3/2 is  TRUE.

c) Putting x  = 1:

$f(1 ) = (\frac{1}{2})(1 ) +\frac{3}{2} = \frac{1}{2} + (\frac{3}{2} )\\\implies f(x) = \frac{3 + 1}{2} = (\frac{4}{2} ) = 2\implies 2 \neq -1$

Hence, f(1)  = -1 is NOT TRUE.

d)Putting x  = 2:  

$f(2 ) = (\frac{1}{2})(2 ) +\frac{3}{2} = 1+ (\frac{3}{2} )\\\implies f(x) = \frac{2 + 3}{2} = (\frac{5}{2} )$

and (5/2) ≠  1

Hence, f(2)  = 1 is NOT TRUE.

e)Putting x  = 4:

 $f(4 ) = (\frac{1}{2})(4 ) +\frac{3}{2} = 2 + (\frac{3}{2} )\\\implies f(x) = \frac{4 + 3}{2} = (\frac{7}{2} )$

Hence, f(4)  = 7/2  is  TRUE.