Answer:
see below
Step-by-step explanation:
1)
set A is already a set of positive odd numbers below 10 so the intersection of the sets is simply {1,3,5,7,9}
2)
this ask, what do sets A,B, and C have in common?
every set has yellow and green so the intersection is
{yellow, green}
3+4x=15
4x=15-3
4x=12
x=12/4
x=3
The check is:
<span>If x=3 then, </span>
3+ (4 X 3)=15
<span>3+12=15</span>
probability that the persons IQ falls between 110 and 130 is 0.2286 .
<u>Step-by-step explanation:</u>
Step 1: Sketch the curve.
The probability that 110<X<130 is equal to the blue area under the curve.
Step 2:
Since μ=100 and σ=15 we have:
P ( 110 < X < 130 )=P ( 110−100 < X−μ < 130−100 )
⇒ P ( (110−100)/15< (X−μ)/σ<(130−100)/15)
Since Z = (x−μ)/σ , (110−100)/15 = 0.67 and (130−100)/15 = 2 we have:
P ( 110<X<130 ) = P ( 0.67<Z<2 )
Step 3: Use the standard normal table to conclude that:
P ( 0.67<Z<2 )=0.2286
Therefore, probability that the persons IQ falls between 110 and 130 is 0.2286 .
