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skelet666 [1.2K]
4 years ago
6

Rayza buys 6 simialar notebooks for $15.how much does she pay for each notebook?

Mathematics
1 answer:
andrew-mc [135]4 years ago
7 0
She would pay $2dollors and 5 cents bc 15÷6 is 2.5 so your answer would be 2.5
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If y=m^4=n^3 and y is greater than 1, then mn=
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The useful property in multiplication is that 1 raised to any number will always be equal to 1. Thus, if y is equal to 1, m and n are also equal to 1. But if y is greater than 1, then m and n would also, consequently, be greater than 1 but less than y. This is because the base number of an exponent must be less in value than the answer. However, if m and n are multiplied, then the product would be greater than 1 but still less than y. 

Let's take an example to prove this point.

Suppose y=5, then
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n = ∛5 = 1.7

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3 0
3 years ago
Annual starting salaries for college graduates is unknown. Assume that a 95% confidence interval estimate of the population mean
kumpel [21]

Answer:

A sample of 217 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

If the population standard deviation is $3,750 how large should the sample be if margin of error is $500

We have that \sigma = 3750.

We need a sample of n, and n is found when M = 500. So

M = z*\frac{\sigma}{\sqrt{n}}

500 = 1.96*\frac{3750}{\sqrt{n}}

500\sqrt{n} = 1.96*3750

\sqrt{n} = \frac{1.96*3750}{500}

(\sqrt{n})^{2} = (\frac{1.96*3750}{500})^{2}

n = 216.1

Rounding up

A sample of 217 is needed.

4 0
3 years ago
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