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DENIUS [597]
3 years ago
14

If the signs of the coordinates of collinear points P(-6,-2), Q(-5,2), and R (-4,6) reversed, are the 3 new points still colline

ar?

Mathematics
2 answers:
Strike441 [17]3 years ago
6 0

If all the points have the signs reversed, therefore this means that the whole line is reflected about an axis. Since all are reflected therefore this further means that the new points are still collinear.

 

We can prove this by plotting the points:

P’(6,2), Q(5,-2), R(4,-6)

<span>From the graph, they are in 1 line hence collinear.</span>

ANTONII [103]3 years ago
5 0

Answer:

The new points also collinear.

Step-by-step explanation:

The given points are P(-6,-2), Q(-5,2), and R (-4,6) are collinear.

If three point are collinear, then

x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)=0

If the signs of the coordinates of collinear points P(-6,-2), Q(-5,2), and R (-4,6) reversed, then the new coordinates are P'(6,2), Q'(5,-2), and R'(4,-6)

Using the formula, check whether the new points are collinear or not.

6(-2-(-6))+5(-6-2)+4(2-(-2))=0

6(-2+6)+5(-8)+4(2+2)=0

6(4)+5(-8)+4(4)=0

24-40+16=0

0=0

Since LHS=RHS, therefore the new points are collinear.

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A persons blood type is denoted with A, B, and O, and the symbols + and — The blood type A+ is read as A positive the blood type
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6. O+ to A+ donors = 90 to 45; 90 : 45 and 90/45

7. AB- donors to AB+ donors = 4 to 6; 4 : 6 and 4/6

8. B+ to total donors = 20 to 195; 20 : 195 and 20/195

9. O- donors to A- donors = 9 to 21; 9 : 21 and 9/21

10. B- donors to B+ donor = 0 to 20; 0 : 20 and 0/20

11. O- donors to total donors = 9 to 195; 9 : 195 and 9/195

12. A+ donors and B+ donors to AB+ donors = 65 to 6; 65 : 6 and 65/6

13. A- donors and B- donors to AB- donors = 21 to 4; 21 : 4 and 21/4

14. the ratio 90/9 is a comparison of O+ donors to O- donors

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A ratio is a relationship where for every x unit of one quantity there are y units of another quantity. A ratio can be written in three ways:

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For the given questions;

6. O+ to A+ donors = 90 to 45; 90 : 45 and 90/45

7. AB- donors to AB+ donors = 4 to 6; 4 : 6 and 4/6

8. B+ to total donors = 20 to 195; 20 : 195 and 20/195

9. O- donors to A- donors = 9 to 21; 9 : 21 and 9/21

10. B- donors to B+ donor = 0 to 20; 0 : 20 and 0/20

11. O- donors to total donors = 9 to 195; 9 : 195 and 9/195

12. A+ donors and B+ donors to AB+ donors

A+ donors and B+ donors to = 45 + 20 = 65

therefore, A+ donors and B+ donors to AB+ donors = 65 to 6; 65 : 6 and 65/6

13. A- donors and B- donors to AB- donors

A- donors and B- donors = 21 + 0= 21

therefore, A- donors and B- donors to AB- donors = 21 to 4; 21 : 4 and 21/4

14. O+ donors = 90; O- donors = 9

therefore, the ratio 90/9 is a comparison of O+ donors to O- donors

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