Answer:
68.26% of the parts will have lengths between 3.8 in. and 4.2 in.
Step-by-step explanation:
The lengths of a lawn mower part are approximately normally distributed

Standard deviation =
We are supposed to find What percentage of the parts will have lengths between 3.8 in. and 4.2 in . i.e. P(3.8<x<4.2)
Formula : 
At x = 3.8

Z=-1
Refer the z table for p value
p value =0.1587
At x =4.2

Z=1
Refer the z table for p value
p value =0.8413
P(3.8<x<4.2)=P(x<4.2)-P(x<3.8)=0.8413-0.1587=0.6826
So, 68.26% of the parts will have lengths between 3.8 in. and 4.2 in.
2^(1+2n)
2^(1+0) = 2
2^(1+2) = 2^3 = 8
2^(1+4) = 2^5 = 32
32 = 1 x 32, 2 x 16, or 4 x 8. Factors of 32: 1, 2, 4, 8, 16, 32
Hope I heled! :)
9514 1404 393
Answer:
see attached
Step-by-step explanation:
The first two x-values, -4 and 0, fall in the first part of the function definition.
There is no function definition for x = 4, as the second part only applies for x > 4.
The last x-value, 8, falls in the second part of the function definition.
The function is evaluated by putting the x-value where x is in the expression and doing the arithmetic. For example, ...
h(-4) = -(-4+1)^2 +7 = -(-3)^2 +7 = -9 +7 = -2
h(0) = 6
h(4) = undefined
h(8) = -8/3