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3 years ago

A car moves at 45 miles per hour. The time and the distance it travels are recorded.

Mathematics

1 answer:

irinina [24]3 years ago

4 0

Answer:

the distance

Step-by-step explanation:

More time care travels, more distance it goes. So distance depends of the time.

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Find the inflection point of the function of f(x) = x³ -6x² +12x

Wewaii [24]

Points of inflections are zeroes of the second derivative. We have:

$f(x)=x^3-6x^2+12x\implies f'(x)=3x^2-12x\implies f''(x)=6x-12$

So, the second derivative equals zero if and only if

$f''(x)=0\iff 6x-12=0 \iff 6x=12 \iff x=2$

So, this is the only point of inflection of this function.

5 0

3 years ago

8. To make a homemade all-purpose household cleaner, you can mix the

Strike441 [17]

Answer:

Could you link the table?

Step-by-step explanation:

4 0

3 years ago

A cryptographic hash takes a message as input and produces a fixed-length string as output, called the digital fingerprint. A br

Allushta [10]

Answer:

$1.85x10^{19}$ attempts are required to find a matching pair if the digital fingerprint is 64 bits long.

$3.40*10^{38}$ attempts are required to find a matching pair if the digital fingerprint is 128 bits long.

Step-by-step explanation:

Each bit has two options. So

How many attempts are required to find a matching pair if the digital fingerprint is 64 bits long?

So for each of the 64 bits, we have the following number of options.

2 - 2 - 2 - 2 -... - 2

So, in all, there are

$T = 2^{64} = 1.85x10^{19}$

options.

So, $1.85x10^{19}$ attempts are required to find a matching pair if the digital fingerprint is 64 bits long.

128 bits long?

Using the same logic as the first question.

$T = 2^{128} = 3.40*10^{38}$

So, $3.40*10^{38}$ attempts are required to find a matching pair if the digital fingerprint is 128 bits long.

5 0

3 years ago

(-6127) + _____. = (-6127)

vredina [299]

Answer:

(-6127) + 0 = (-6127)

(+18) + 2 = (+20)

(+27) - 7 = (+20)

(+63) + (-13) = (+50)

(+21) - 4 = (+17)

Step-by-step explanation:

5 0

3 years ago

Brook makes this conjecture: Because the angles are equal, the proportion of area of each sector relative to the area of the giv

AnnZ [28]

Answer:

The Brooks conjecture is true as the proportion of the area of a sector to the area of a circle is only dependent on the angle.

Step-by-step explanation:

The area of a sector for a radius r and an angle θ is given as

$\Delta Sector=\dfrac{1}{2}r^2\theta$

Whereas the area of a circle for a radius r is given as

$\Delta Circle=\pi r^2$

Now the ratio is given as

$\dfrac{\Delta Sector}{\Delta Circle}=\dfrac{\dfrac{1}{2}r^2\theta}{\pi r^2}$

Here as r is the radius of the circle and it is the same therefore the above ratio is simplified to

$\dfrac{\Delta Sector}{\Delta Circle}=\dfrac{\theta}{2\pi }$

Here as π is constant the only variable here is θ. Thus according to Brooks conjecture when the angles are equal, the proportion of area of each sector relative to the area of the given circle is also equal is true.

6 0

3 years ago