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Iteru [2.4K]
2 years ago
15

How do I solve 8n= -3m + 1 ; n= -2, 2, 4

Mathematics
2 answers:
Dennis_Churaev [7]2 years ago
6 0
8n = -3m + 1
n = -2, 2,4
first add -2, 2 and 4 which = 4 
then do 8(4) = -3m +1 which makes 24 = -3m +1 so subtract 1 on both sides then you have 23 = -3m divde -3 on both sides which equal -7.66 or 8 
SVEN [57.7K]2 years ago
3 0
I'm thinking you want us to solve for m when n=-2 and 2 and 4

let's solve for m first
minus 1 from both sides then divide by -3
m=\frac{8n-1}{-3}

so for n=-2
m=\frac{8(-2)-1}{-3}=\frac{-16-1}{-3}=\frac{-17}{-3}=\frac{17}{3}
when n=-2, m=17/3

for n=2
m=\frac{8(2)-1}{-3}=\frac{16-1}{-3}=\frac{15}{-3}=-5
m=-5 when n=2

for n=4
m=\frac{8(4)-1}{-3}=\frac{32-1}{-3}=\frac{31}{-3}=\frac{-31}{3}
m=-31/3 when n=4
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