Question

How do I solve 8n= -3m + 1 ; n= -2, 2, 4

Answer 1

8n = -3m + 1
n = -2, 2,4
first add -2, 2 and 4 which = 4 
then do 8(4) = -3m +1 which makes 24 = -3m +1 so subtract 1 on both sides then you have 23 = -3m divde -3 on both sides which equal -7.66 or 8 

Answer 2

I'm thinking you want us to solve for m when n=-2 and 2 and 4

let's solve for m first
minus 1 from both sides then divide by -3
$m=\frac{8n-1}{-3}$

so for n=-2
$m=\frac{8(-2)-1}{-3}=\frac{-16-1}{-3}=\frac{-17}{-3}=\frac{17}{3}$
when n=-2, m=17/3

for n=2
$m=\frac{8(2)-1}{-3}=\frac{16-1}{-3}=\frac{15}{-3}=-5$
m=-5 when n=2

for n=4
$m=\frac{8(4)-1}{-3}=\frac{32-1}{-3}=\frac{31}{-3}=\frac{-31}{3}$
m=-31/3 when n=4