Answer:
d-250x5=i dont know
Step-by-step explanation:
The function is (-x+3)/ (3x-2) and we get f(1)=1 and differentiation is f'(x)=-7/ (9x²- 12x+4).
Given that,
The function is (-x+3)/ (3x-2)
We have to find f(1) and f'(x).
Take the function expression
f(x)= (-x+3)/ (3x-2)
Taking x as 1 value
f(1)= (-1+3)/(3(1)-2)
f(1)=2/1
f(1)=1
Now, to get f'(x)
With regard to x, we must differentiate.
f(x) is in u/v
We know
u/v=(vu'-uv')/ v² (formula)
f'(x)= ((3x-2)(-1)- (-x+3)(3))/ (3x-2)²
f'(x)= ((-3x+2)-(-3x+9))/ 9x²- 12x+4
f'(x)=(-3x+2+3x-9)/ 9x²- 12x+4
f'(x)=2-9/ (9x²- 12x+4)
f'(x)=-7/ (9x²- 12x+4)
Therefore, The function is (-x+3)/ (3x-2) and we get f(1)=1 and differentiation is f'(x)=-7/ (9x²- 12x+4).
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The answer is 24.5
Hope this helps :)
a^2 + b^2 = c^2
Let c = hypotenuse = 2x
One of the legs = x. Let a or b = x.
I will let a = x. We can then say that b = 3.
3^2 + x^2 = (2x)^2
9 + x^2 = 4x^2
9 = 4x^2 - x^2
9 = 2x^2
9/2 = x^2
sqrt{9/2} = sqrt{x^2}
3/sqrt{2} = x
Rational denominator.
[3•sqrt{2}]/2 = x = a
Side 3 is given to be 3 feet. So, b = 3.
Hypotenuse = 2x
Hypotenuse = 2([3•sqrt{2}]/2)
Hypotenuse = 3•sqrt{2}
Understand?
The three sides are 3, [3•sqrt{2}]/2 and
3•sqrt{2}.
