Answer:
The answer is below
Step-by-step explanation:
We need to prove that:
(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.
Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.
Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A
Given:
Area of a right triangle = 18 sq. inches
Length of one leg = 6 inches
To find:
The length of another leg.
Solution:
We know that, the area of a triangle is
In a right angle triangle, the area of the triangle is
Putting A=18 and , we get
Divide both sides by 3.
Both legs are equal so the given triangle is an isosceles right triangle.
If the triangle is not isosceles triangle, then the length of legs are factors of 36 because half of 36 is 18.
Therefore, the possible pairs of legs are 1 and 36, 2 and 18, 3 and 12, 4 and 9, 6 and 6, 9 and 4, 12 and 3, 18 and 2, 36 and 1.
The given terms are two terms apart, so their difference is twice the difference of adjacent terms.
The value of d is 4.