X basketball players who tried out for the team were chosen. They were distributed into 5 groups each. In one of the groups, 2 of the teammates left. How many players did that group have?
I'm sure you can word this even better.. I'm just in a rush.
We are given the equations 3x+5y=-3 and x-5y=-5.
Both equations have a 5y term which allows us to easily solve the system by elimination. To do so we will add the equations together like a simple addition problem by adding the x terms together, the y terms together, and the integer answers together.
3x + 5y = -3
+x - 5y = -5
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4x + 0y = -8
The y terms cancel out since one is positive and one is negative. Now we can solve for x.
4x = -8

x = -2
Now plug -2 in for x in one of the original equations to find y.
(-2) - 5y = -5
-5y = -3
y = 3/5
Our answer as an ordered pair is (2, 3/5)
Answer:
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Answer:
(-2, -3), (1, 6), (2, 9) are plotted in the attached graph
Step-by-step explanation:
For x = -2, y = 3(-2) +3 = -3. The ordered pair is (-2, -3).
For x = 1, y = 3(1) +3 = 6. The ordered pair is (1, 6).
For x = 2, y = 3(2) +3 = 9. The ordered pair is (2, 9).
The graph is attached.