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Nataliya [291]
3 years ago
12

The lengths of salamanders have a normal distribution with mean 15cm, and standard deviation 2cm. What length of salamander woul

d place it at the 80th percentile of salamander lengths?
Mathematics
1 answer:
Law Incorporation [45]3 years ago
4 0

Answer:

16.68 cm

Step-by-step explanation:

Given that :

Mean , m = 15

Standard deviation, s = 2

Length of salamander that would Place it at 80% of salamander length :

P(Z ≤ x) = 0.8

Zscore equivalent to 0.8 = 0.842

Using the relation :

Zscore = (x - m) /s

0.842 = (x - 15) / 2

1.684 = x - 15

Add 15 to both sides

1.684 + 15 = x - 15 + 15

16.684 = x

Hence, x = 16.68 cm

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Answer: a constant

Step-by-step explanation:

A constant is a numerical expression like 2, 0,78 etc .

A variable is a alphabetical expression that vary like a,b,c,d,x,y,z.

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(2.5 points) The probability that an airplane accident which is due to structural failure is diagnosed correctly is 0.85 and the
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Step-by-step explanation:

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p = (0.3*0.85)/((0.3*0.85) + (0.7*0.35))

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