1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nataliya [291]
3 years ago
12

The lengths of salamanders have a normal distribution with mean 15cm, and standard deviation 2cm. What length of salamander woul

d place it at the 80th percentile of salamander lengths?
Mathematics
1 answer:
Law Incorporation [45]3 years ago
4 0

Answer:

16.68 cm

Step-by-step explanation:

Given that :

Mean , m = 15

Standard deviation, s = 2

Length of salamander that would Place it at 80% of salamander length :

P(Z ≤ x) = 0.8

Zscore equivalent to 0.8 = 0.842

Using the relation :

Zscore = (x - m) /s

0.842 = (x - 15) / 2

1.684 = x - 15

Add 15 to both sides

1.684 + 15 = x - 15 + 15

16.684 = x

Hence, x = 16.68 cm

You might be interested in
(15y^0 x^-3 z^2/ 3x^3 y^7 z^1/2)^2
ArbitrLikvidat [17]
Hello! For this you are just going to do this step by step, and remember to use PEMDAS. That is the order in which you should do the math. The abbreviation stands for  Parenthesis, exponents, multiplication, division, addition and subtraction. So lets get started!
<span><span>(<span><span><span><span>(<span><span><span><span><span>15<span>y0</span></span><span>x<span>−3</span></span></span><span>z2</span></span>3</span><span>x3</span></span>)</span><span>(<span>y7</span>)</span></span><span>z1</span></span>2</span>)</span>2</span><span>=<span><span><span>254</span><span><span><span>x6</span><span>y14</span></span><span>z6</span></span></span><span>x6</span></span></span><span>=<span><span>254</span><span><span>y14</span><span>z6</span></span></span></span>

Hope this helps!! If you need any more help or further explanation just let me know!! :)
 

6 0
4 years ago
What do yall want for christmas​
vlabodo [156]
A PS5 YKYKYKKYykykyykylyk
4 0
3 years ago
Read 2 more answers
Factor completely x^3 + 1/8
maksim [4K]

Answer:

((2 x + 1) (4 x^2 - 2 x + 1))/8

Step-by-step explanation:

Factor the following:

x^3 + 1/8

Put each term in x^3 + 1/8 over the common denominator 8: x^3 + 1/8 = (8 x^3)/8 + 1/8:

(8 x^3)/8 + 1/8

(8 x^3)/8 + 1/8 = (8 x^3 + 1)/8:

(8 x^3 + 1)/8

8 x^3 + 1 = (2 x)^3 + 1^3:

((2 x)^3 + 1^3)/8

Factor the sum of two cubes. (2 x)^3 + 1^3 = (2 x + 1) ((2 x)^2 - 2 x + 1^2):

((2 x + 1) ((2 x)^2 - 2 x + 1^2))/8

1^2 = 1:

((2 x + 1) ((2 x)^2 - 2 x + 1))/8

Multiply each exponent in 2 x by 2:

((2 x + 1) (2^2 x^2 - 2 x + 1))/8

2^2 = 4:

Answer:  ((2 x + 1) (4 x^2 - 2 x + 1))/8

5 0
3 years ago
Read 2 more answers
HURRY NEED HELP ASAP I WILL GIVE BRAINLIEST!!
Anuta_ua [19.1K]
Identify the angle variable to use.
Write an equation.
Solve the equation for the variable.
Find the unknown angle measure.
7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=3%28m%20%2B%2010%29%20-%202%28m%20-%20n%29%20%20%5C%3A%20what%20%5C%3A%20is%20%5C%3A%20the%20%
Umnica [9.8K]

Answer:

5m+30+2n

Step-by-step explanation:

3m+30 and - 2m+2n

5m+30+2n

8 0
3 years ago
Other questions:
  • The Sears Tower, at 1,451 feet, is one of the tallest structures in the United States. A penny is thrown from the top of the tow
    12·1 answer
  • If AC = 18 and CD = 5, AD = [?]<br> 8<br> Enter
    7·1 answer
  • 2 1/3 divided by 1/4
    7·2 answers
  • Which expression converts StartFraction pi Over 4 EndFraction radians to degrees?
    8·2 answers
  • Can somebody help me with the Math's questions with Forming and Solving Equations? Thanks
    9·1 answer
  • Ou have traveled 25 miles in 2 minutes and come to a standstill. What was your initial velocity?
    10·1 answer
  • Is this triangle a SSS, SAS, ASA, AAS, or HL?
    9·2 answers
  • Eight inches of snow fell in five hours. Write the number of inches per hour.
    13·1 answer
  • I need help please urgent
    10·1 answer
  • Lowest term fractio 15/20​
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!