Question

A radio station runs a promotion at an auto show with a money box with 12 ​$25 ​tickets, 11 ​$5 ​tickets, and 10 ​$1 tickets. The box contains an additional 20 ​"dummy" tickets with no value. Find the probability that three ​$25 prizes are chosen.

Answer 1

Answer:

P(three ​$25 prizes are chosen)=$\frac{12}{53}$

Step-by-step explanation:

A radio station runs a promotion at an auto show with a money box with 12 ​$25 ​tickets, 11 ​$5 ​tickets, and 10 ​$1 tickets.

20 dummy tickets

total tickets = 12+11+10+20=53

3 $25 prizes are chosen

there are 12 , $25 tickets

probability = number of occurrences / total occurrences

P(three ​$25 prizes are chosen)=$\frac{12}{53}$