A radio station runs a promotion at an auto show with a money box with 12 $25 tickets, 11 $5 tickets, and 10 $1 tickets. Th

Question

3 years ago

14

e box contains an additional 20 "dummy" tickets with no value. Find the probability that three $25 prizes are chosen.

1 answer:

Artist 52 [7] · Answer 1 · 2021-12-03T16:36:08+03:00

Answer:

P(three $25 prizes are chosen)= $\frac{12}{53}$

Step-by-step explanation:

A radio station runs a promotion at an auto show with a money box with 12 $25 tickets, 11 $5 tickets, and 10 $1 tickets.

20 dummy tickets

total tickets = 12+11+10+20=53

3 $25 prizes are chosen

there are 12 , $25 tickets

probability = number of occurrences / total occurrences

P(three $25 prizes are chosen)= $\frac{12}{53}$

A radio station runs a promotion at an auto show with a money box with 12 ​$25 ​tickets, 11 ​$5 ​tickets, and 10 ​$1 tickets. Th