The difference of two numbers is 3. their sum is 13. find the numbers. creater the system and solve
1 answer:
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Let us translate the words into mathematics!
The difference of 2 numbers is 3
x - y = 3
The sum of 2 numbers is 13
x + y = 13
(eq. 1) x - y = 3
(eq.2) x + y = 13
eq. 1 + eq.2 ⇒ x - y = 3
+ x + y = 13 ( -y and +y cancels out )
2x = 16
x = 8
We have the value of x, simply substitute it in either of the formulae to find y
x - y = 3 , 8 - y = 3 , 8 - 3 = y , 5 = y
x + y = 13 , 13 - 8 = y , 5 = y
x = 8 , y = 5
Let us translate the words into mathematics!
The difference of 2 numbers is 3
x - y = 3
The sum of 2 numbers is 13
x + y = 13
(eq. 1) x - y = 3
(eq.2) x + y = 13
eq. 1 + eq.2 ⇒ x - y = 3
+ x + y = 13 ( -y and +y cancels out )
2x = 16
x = 8
We have the value of x, simply substitute it in either of the formulae to find y
x - y = 3 , 8 - y = 3 , 8 - 3 = y , 5 = y
x + y = 13 , 13 - 8 = y , 5 = y
x = 8 , y = 5
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The answer is 9.
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A₂ - the area after the change,
A₁ - the area before the change,
l₂ - the dimension after the change,
l₁ - the dimension before the change.
It is given:
l₁ = 1 cm
l₂ = 3 cm
Let's use this formula for the mentioned triangle:
Therefore, the area of the triangle was multiplied by 9.
To calculate this, we will use Galileo's square cube law, used to describe the change of the area or the volume of the shape, when their dimensions increase or decrease. The formula used for change of the area is
A₂ - the area after the change,
A₁ - the area before the change,
l₂ - the dimension after the change,
l₁ - the dimension before the change.
It is given:
l₁ = 1 cm
l₂ = 3 cm
Let's use this formula for the mentioned triangle:
Therefore, the area of the triangle was multiplied by 9.