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3 years ago

a wall on the side of a building is made up of 52 rows of bricks with 44 bricks in each row. how many bricks make up the wall

Mathematics

2 answers:

Mashcka [7]3 years ago

7 0

Just do 52 x 44. Which equals 2,288.

sveta [45]3 years ago

5 0

There are a total of 2,288 bricks that make up the wall.

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im not sure wether to replace the minus signs with addition, so if you could help me that would be nice :) 1.2y+4.5-3.4y-6.3

Elenna [48]

Answer:

-2.2y - 1.8

Step-by-step explanation:

We are to simplify the expression:

1.2y + 4.5 - 3.4y - 6.3

Collect like terms:

1.2y - 3.4y + 4.5 - 6.3

Simplify:

-2.2y - 1.8

That is the answer.

6 0

3 years ago

Find the next 2 terms in the Geometric sequence 20,30,45 ...

DochEvi [55]

Answers:

The next two terms are 67.5 and 101.25 in that order.

===========================================

Explanation:

Divide the second term over the first to get 30/20 = 1.5

Divide the third term over the second term to get 45/30 = 1.5

The common ratio is 1.5, which means we multiply 1.5 by each term to get the next term

-------

fourth term = 1.5*(third term) = 1.5*45 = 67.5

fifth term = 1.5*(fourth term) = 1.5*67.5 = 101.25

-------

As a shortcut you can plug n = 4 and n = 5 into the function t(n) = 20*(1.5)^(n-1) to get the fourth and fifth terms respectively.

3 0

3 years ago

While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem

Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = population proportion.

So, Null Hypothesis, $H_0$ : p = 0.013 {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, $H_A$ : p > 0.013 {means that this is an unusually high number of faulty modems}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion faulty modems= $\frac{10}{367}$ = 0.027

n = sample of modems = 367

So, the test statistics = $\frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }$

= 2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0

4 years ago

Thabo invests R50000 at the rate of 5% per annum compound interest periodically every six months.How many years does it take to

lina2011 [118]

Answer:

50000-5%=49500 pls like

7 0

3 years ago

some numbers added to -11 is 37.divide this number by -12.then multiply by -8.what is the final number?

LUCKY_DIMON [66]

Since some number added to -11 is 37, we must do 37- (-11), which is 48. Then we check our work and find that 48+-11 is indeed 37. Now we divide 48 by -12, which is -4, multiply by -8 and get a final answer of 32.

6 0

3 years ago