Answer:
<em>The probability is 0.89 or 89%</em>
Step-by-step explanation:
<u>Probability</u>
There are n=27 students in a certain Algebra 2 class. 18 out of them play basketball and 16 of them play baseball.
We also know 3 students play neither sport. This leaves 27-3=24 students playing sports.
The probability that a randomly chosen student plays basketball or baseball is:

Simplifying:

The probability is 0.89 or 89%
The average is (0.76+0.88) / 2 = 1.64 / 2 = 0.82
The upside down U means the numbers the sets have in common.
Do what is in parenthesis first:
(B ∩ C) = 6 is the only common number in set B and Set C.
A ∩ (B ∩ C) = Would be all the numbers in A plus the number 6 from (B ∩ C).
The answer would be A) {1, 3, 5, 6, 7, 9}