<h2>fock you dumb hooman.......</h2>
The common denomenators of the denomenaotrs is 6(x+1)
times both the fraction by (6(x+1))/(6(x+1))
we get
(5(6)(x+1))/((x+1)+6)=(30(x+1))/(x+7)=(30x+30)/(x+7)
Answer:
The experimental probability that the next child to enroll will be a preschooler is 40%
P(E) = 40%
Step-by-step explanation:
What is Experimental Probability?
Experimental probability is basically the ratio of the number of outcomes occurred to the total number of trials in an actual experiment.
In this problem we are given that out of the last 10 children to enroll at the day care center, there are 4 children who belong to the category of preschoolers.
We are asked to find the experimental probability that the next child to enroll will be a preschooler.
The required experimental probability is given by

Where number of desired outcomes are 4 and total number of outcomes are 10
So the probability is

Therefore, the experimental probability that the next child to enroll will be a preschooler is 40%
Plot a point at (0,-1)
Then from that point, go down 3 points, and to the right one point. Repeat that until you hit the bottom of the graph or run out of room. From the first point (0,-1), go up 3 and to the left 1 until you run out of room on the graph. Should be a straight line
solution
Find the equivalent ratio for 64%. Write your answer in simplest form.
For this case we can do the following:
64% = 64/100
And if we simplify we got:
64/100 = 32/50 = 16/25 = 0.64