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Mashcka [7]
3 years ago
6

Which polygons can be mapped onto each other by similarity transformations?

Mathematics
2 answers:
Fittoniya [83]3 years ago
8 0

Solution:

Two polygons are said to be similar if ratio of their corresponding sides are same and their interior angles are congruent.

Consider Polygon 1 and Polygon 4

AB= DE= 8 units, AE= 6 units,

PT=QR= 4 Units, PQ= 3 Units

\frac{AB}{PT}=\frac{DE}{QR}=\frac{AE}{PQ}=\frac{BC}{SR}=\frac{CD}{TS}

So, Polygon 1 ≅ Polygon 4

Now, Consider Polygon 2 and Polygon 3

LM=KO=6 units, LK=4 units

GF= 4 units, GH=FJ =4 Units

As you can see that polygon 2 and polygon 4 doesn't have corresponding proportional sides i.e \frac{6}{4}\neq \frac{4}{4}<em>.</em>

So, Polygon 2  is not congruent to Polygon 4.


Julli [10]3 years ago
3 0
Polygon A,B,C,D,E and polygon L,M,N.O.K
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PLEASE SHOW WORK
CaHeK987 [17]

(C)

Step-by-step explanation:

The volume of the conical pile is given by

V = \dfrac{\pi}{3}r^2h

Taking the derivative of V with respect to time, we get

\dfrac{dV}{dt} = \dfrac{\pi}{3}\dfrac{d}{dt}(r^2h)

\:\:\:\:\:\:\:= \dfrac{\pi}{3}\left(2rh\dfrac{dr}{dt} + r^2\dfrac{dh}{dt}\right)

Since r is always equal to h, we can set

\dfrac{dr}{dt} = \dfrac{dh}{dt}

so that our expression for dV/dt becomes

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Solving for dh/dt, we get

\dfrac{dh}{dt} = \dfrac{1}{\pi r^2}\dfrac{dV}{dt}

\:\:\:\:\:\:\:= \dfrac{1}{9\pi\:\text{m}^2}(36\:\text{m}^3\text{/s})

\:\:\:\:\:\:\:= \dfrac{4}{\pi}\:\text{m/s}

7 0
3 years ago
the volume of a prism changes from 20 to 540 after a dilation. What was the scale factor of the dilation?
pashok25 [27]
Hello!

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540 / 20 = 27

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The answer is 27

Hope this helps!
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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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