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SIZIF [17.4K]
3 years ago
10

Ms. Everett found birthday cards in packs of 6 and envelops in packs of 9. If she wants to have the same number of cards and env

elops, what is the minimum number of each she can purchase?
Mathematics
2 answers:
Solnce55 [7]3 years ago
7 0
You need to do this LCM(least common multiples)

6,12,18,24,30,36
9,18,27,36,45,54

18 is your answer.
Mandarinka [93]3 years ago
6 0
The minimum she can buy for the pack of 6 is 3 and the minimum for the pack of 9 is 2.
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-2 minus 0.7 what is your total
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The answer would be -2.7

Step-by-step explanation:

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What is the range of the function f(x) = 2 – 2 when the domain is {0, 2, 4}? O {-1, 2, 14} {3, 6, 8} {-2, 2, 6) All real numbers
devlian [24]

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F = 0

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5 0
3 years ago
Read 2 more answers
Which number gives you a rational sum when you add it to 4/7
olya-2409 [2.1K]

Answer:

-2/12

Step-by-step explanation:

Given Rational Numbers are 4/7 and 13/7

Adding them we get 4/7+13/7

= (4+13)/7

= 17/7

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Add 5/12 and -3/12?

Given Rational Numbers are 5/12, -3/12

Adding them we get 5/12+(-3)/12

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= -2/12

4 0
3 years ago
For a certain​ candy, 15​% of the pieces are​ yellow, 1010​% are​ red, 2020​% are​ blue, 55​% are​ green, and the rest are brown
MatroZZZ [7]
A) the probability it is brown would be 50%; the probability it is yellow or blue would be 35%; the probability it is not green is 95%; the probability it is striped is 0%.
B) the probability of all brown would be 12.5%; the probability that the third one is the first red one drawn is 8.1%; the probability that none are yellow is 61.4%; the probability that at least one is green is 14.3%.

Explanation:
A) The probability that it is brown is the percentage of brown we have.  Brown is not listed, so we subtract what we are given from 100%:
100-(15+10+20+5) = 100-(50) = 50%.  The probability that one drawn is yellow or blue would be the two percentages added together:  15+20 = 35%.  The probability that it is not green would be the percentage of green subtracted from 100:  100-5=95%.  Since there are no striped candies listed, the probability is 0%.
B) Since we have an infinite supply of candy, we will treat these as independent events.  All 3 being brown is found by taking the probability that one is brown and multiplying it 3 times:
0.5*0.5*0.5 = 0.125 = 12.5%.  
To find the probability that the first one that is red is the third one drawn, we take the probability that it is NOT red, 100-10 = 90% = 0.9, for the first two, and the probability that it IS red, 10% = 0.1, for the last:
0.9*0.9*0.1 = 0.081 = 8.1%.

The probability that none are yellow is found by raising the probability that the first one is not yellow, 100-15=85%=0.85, to the third power:

0.85^3 = 0.614 = 61.4%.

The probability that at least one is green is computed by subtracting 1-(probability of no green).  We first find the probability that all three are NOT green:
0.95^3 = 0.857375
1-0.857375 = 0.143 = 14.3%.
3 0
3 years ago
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