Ms. Everett found birthday cards in packs of 6 and envelops in packs of 9. If she wants to have the same number of cards and env
elops, what is the minimum number of each she can purchase?
2 answers:
You need to do this LCM(least common multiples)
6,12,18,24,30,36
9,18,27,36,45,54
18 is your answer.
The minimum she can buy for the pack of 6 is 3 and the minimum for the pack of 9 is 2.
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Answer:
b-m b-c b-r
Step-by-step explanation:
Second side= x
First side = 2x
Third side = x+5
x+2x+x+5=49
4x=44
x=11
1st side= 22
2nd side = 11
3rd side = 16
Answer:
it would have to be c....
Step-by-step explanation:
Answer:
7
Step-by-step explanation:
Working backwards:
19 + 9 = 28
28/ 4 = 7
Checking work:
7 x 4 = 28
28 - 9 = 19
Answer:
A≈153.94cm²
Step-by-step explanation:
A=πr2
d=2r
Solving forA
A=1
4πd2=1
4·π·142≈153.93804cm²
