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2 years ago

How do you find a missing angle or side length

Mathematics

2 answers:

notka56 [123]2 years ago

6 0

Since you said angle, I assume you mean a triangle, so:

Take the number of the angles you have and add them, then, subtract it by 180. It gives you the missing angle of your triangle!

Illusion [34]2 years ago

5 0

Add the two known angles

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0.9 1.8 2.9

Step-by-step explanation:

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2 years ago

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What is the inequality of 6x-4<8?

Kobotan [32]

6x - 4 < 8

Add 4 to both sides:
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2 years ago

Prove :<br>sin²θ + cos²θ = 1<br><br><br>thankyou ~

Gnom [1K]

Answer:

See below

Step-by-step explanation:

Here we need to prove that ,

$\sf\longrightarrow sin^2\theta + cos^2\theta = 1$

Imagine a right angled triangle with one of its acute angle as $\theta$ .

The side opposite to this angle will be perpendicular .
Also we know that ,

$\sf\longrightarrow sin\theta =\dfrac{p}{h} \\$

$\sf\longrightarrow cos\theta =\dfrac{b}{h}$

And by Pythagoras theorem ,

$\sf\longrightarrow h^2 = p^2+b^2 \dots (i)$

Where the symbols have their usual meaning.

Now , taking LHS ,

$\sf\longrightarrow sin^2\theta +cos^2\theta$

Substituting the respective values,

$\sf\longrightarrow \bigg(\dfrac{p}{h}\bigg)^2+\bigg(\dfrac{b}{h}\bigg)^2\\$

$\sf\longrightarrow \dfrac{p^2}{h^2}+\dfrac{b^2}{h^2}\\$

$\sf\longrightarrow \dfrac{p^2+b^2}{h^2}$

From equation (i) ,

$\sf\longrightarrow\cancel{ \dfrac{h^2}{h^2}}\\$

$\sf\longrightarrow \bf 1 = RHS$

Since LHS = RHS ,

Hence Proved !

I hope this helps.

5 0

1 year ago

Van someone help me with this

gizmo_the_mogwai [7]

Answer:

107

Step-by-step explanation:

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2 years ago

Sorry i know it is too blurry but can u at least try

raketka [301]

Answer:

Step-by-step explanation:

Draw your figures the same way as I did, and see if you understand the explanations before writing them down. It's most important to learn from your work :)

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2 years ago