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wel
3 years ago
13

a rectangle shape whose length is 4 inches less than twice its width. the area is 30 square inches. whats the dimension

Mathematics
1 answer:
Ne4ueva [31]3 years ago
5 0
Using the given information, we can say the following:
Width (W) = x
Length (L) = (2x - 4)
Area of Rectangle = L × W
Using this, we can formulate an equation for rectangle in question:
x(2x - 4) = 30
Expand and move everything to one side:
2x² - 4x - 30 = 0
Simplify by dividing everything on both sides by 2:
x² - 2x - 15 = 0
Factorise:
(x + 5)(x - 3) = 0
Set each factor equal to 0 and solve for x:
x + 5 = 0
x = -5 (a dimension cannot be negative so this is not the solution we want)
x - 3 = 0
x = 3 (this is the solution)
x = W = 3"
L = 2x - 4
L = 2(3) - 4
L = 2"

So, the length the rectangle is 2" and the width is 3"
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If you multiply a number by 3 and then subtract 5, you will get 40 what is the number
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Answer:

Number  = 15.

Step-by-step explanation:

Given : If you multiply a number by 3 and then subtract 5, you will get 40.

To find : what is the number.

Solution : We have given if you multiply a number by 3 and then subtract 5, you will get 40.

According to question :

Let the number =  x

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3x -5 = 40

On adding both sides by 5

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On dividing both sides by 3

x =  15.

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