Question

What is the solution to the system of equations below? y = one-half x minus 4 and y = negative 2 x minus 9 (–2, –5) (–2, –3) (2, –3) (2, –13)

Answer 1

We have been given a system of equations $y=\frac{1}{2}x-4$ and $y=-2x-9$. We are asked to find the solution of our given system of equations.

To solve our system of equations, we will equate both equations as:

$\frac{1}{2}x-4=-2x-9$

$\frac{1}{2}x-4+4=-2x-9+4$

$\frac{1}{2}x=-2x-5$

$\frac{1}{2}x+2x=-2x+2x-5$

$\frac{1}{2}x+\frac{4}{2}x=-5$

$\frac{1+4}{2}x=-5$

$\frac{5}{2}x=-5$

$\frac{2}{5}\cdot \frac{5}{2}x=-5\cdot \frac{2}{5}$

$x=-2$

Upon substituting $x=-2$ in equation $y=-2x-9$, we will get:

$y=-2(-2)-9$

$y=4-9$

$y=-5$

Therefore, the solution of our given system of equations would be $(-2,-5)$ and option A is the correct choice.

Answer 2

Answer:

is A: (–2, –5)

Step-by-step explanation:

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