A line that includes the point ( - 4, - 1) has a slope of - 2. What is its equation in point-slope form?

Mathematics

2 answers:

EastWind [94]3 years ago

4 0

Point-Slope equation: y - y₁ = m(x - x₁) ; m is slope and (x₁ ,y₁) is the coordinate

y - (-1) = -2(x - (-4)

y + 1 = -2(x + 4) <em>simplified (two negatives make a positive)</em>

Grace [21]3 years ago

3 0

Point slope form says the line through (a,b) with slope m is

y - b = m(x - a)

Here that's

y - - 1 = -2(x - -4)

Answer: y + 1 = -2(x + 4)

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Solve the equation 3/4x+3-2x = -1/4+1/2x+5

elena55 [62]

Hi there! The answer is x = -1

Let's solve this equation step by step!
$\frac{3}{4} x + 3 - 2x = - \frac{1}{4} + \frac{1}{2} x + 5$

First collect terms.
$- 1 \frac{1}{4} x + 3 = \frac{1}{2} x + 4 \frac{3}{4}$

Subtract (1/2)x from both sides.
$- 1\frac{3}{4} x + 3 = 4 \frac{3}{4}$

Subtract 3 from both sides.
$- 1\frac{3}{4} x = 1 \frac{3}{4}$

And finally divide by -1 3/4
$x = \frac{7}{4} \div - \frac{7}{4} = \frac{7}{4} \times - \frac{4}{7} = - \frac{28}{28} = - 1$