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3 years ago

9

What’s the answer please

2 answers:

Lunna [17]3 years ago

6 0

You could set up a ratio:
$\frac{186}{3} = \frac{x}{1}$
which then becomes:

strojnjashka [21]3 years ago

5 0

Hello there, and thank you for posting your question here on brainly.

She drove 186 miles in 3 hours, to find out how much she drove in 1 hour, you can divide 186 by 3.

186 / 3 = 62

She drove 62 mph / miles per hour.

Hope this helped!! ☺♥

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Find the circumference of a circle whose radius is 4 feet. Use 3.14 for Pi.

slavikrds [6]

Answer:

25.12

Step-by-step explanation:

The formula of the circumference of a circle is: C = 2(pi)(r)

Plug in 3.14 for pi and 4 for the radius.

C = 2(3.14)(4)

Multiply.

C = 25.12

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2 years ago

5. How many pairs of parallel sides does the<br>trapezoid below have?

fgiga [73]

A normal standard trapezoid has 1 pair of parallel sides.

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2 years ago

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A cylinder has a base diameter of 12in and a height of 17in. What is its volume in cubic in, to the nearest tenths place?

Anna35 [415]

Answer:

1922.7 cubic inches

Step-by-step explanation:

The volume of a cylinder can be found with this formula:

V=πr^2h

The radius, r, is half the diameter.

So, 12/2=6

r=6 inches

Then, just plug the numbers in.

V=π(6)^2(17)

V=1922.65

Rounding to the nearest tenth:

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3 0

2 years ago

Which of the following is a solution to 2cos2x − cos x − 1 = 0?

Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, $x = 0^{\circ}$

Step-by-step explanation:

Given that : $2\cos^2x -\cos x -1 =0$

Let $\cos x =y$

then our equation become;

$2y^2-y-1= 0$ .....[1]

A quadratic equation is of the form:

$ax^2+bx+c =0$ .....[2] where a, b and c are coefficient and the solution is given by;

$x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

$y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}$

Simplify:

$y = \frac{ 1 \pm \sqrt{1+8}}{4}$

or

$y = \frac{ 1 \pm \sqrt{9}}{4}$

$y = \frac{ 1 \pm 3}{4}$

or

$y = \frac{1+3}{4}$ and $y = \frac{1 -3}{4}$

Simplify:

y = 1 and $y = -\frac{1}{2}$

Substitute y = cos x we have;

$\cos x = 1$

⇒ $x = 0^{\circ}$

and

$\cos x = -\frac{1}{2}$

⇒ $x = 120^{\circ} \text{and} x = 240^{\circ}$

The solution set: $\{0^{\circ}, 120^{\circ} , 240^{\circ}\}$

Therefore, the solution for the given equation $2\cos^2x -\cos x -1 =0$ is, $0^{\circ}$

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fiasKO [112]

I thought they would be the same so I would go with B. 85

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