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zysi [14]
3 years ago
14

What is the cosine of this problem?

Mathematics
1 answer:
notka56 [123]3 years ago
7 0
X= 9.46
Hope this help you
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A cake recipe requires 2/3 of an ounce of baking powder. How many cakes can be made from a package containing 50 ounces of bakin
AnnZ [28]

Answer:

75

Step-by-step explanation:

Divide 50 by 2/3. Division is the same as asking "how many times can i subtract 2/3 from 59?"

50 \div  \frac{2}{3}

Dividing by a fraction is the same as multiplying by the reciprocal.

50 \times  \frac{3}{2}  = 75

You can subtract 2/3 from 50, 75 times

5 0
3 years ago
Angie ,Blake ,Carlos and daisy went running . Angie ran 1/3 mike, Blake ran 3/5 mile, Carlos ran 7/10 mile, and daisy ran 1/2 mi
Alexxx [7]
Lets find the common demoninator of them all, Its 30!  so 1/3 of 30= 10
3/5 of 30= 18       7/10 of 30= 21      1/2 of 30 = 15

So that means that 7/10 is the biggest out of them all, That means carlos ran the greatest distance!


8 0
3 years ago
Help me please with geometry ​
Yuri [45]

Answer:

Step-by-step explaunfere:

The circumference of a circle is the distance around the outside of the circle. The diameter, and the circumference are the three defining aspects of every circle. Given the radius or diameter and pi you can calculate the circumference.

1- C ≈ 50.27 in

2- C ≈ 31.42 in

3- A ≈ 201.06

4- A ≈ 314.16

5- C = 14π = 43.982 ≈ 44 inches

π (Pi) times the Radius squared: A = π r2

or, when you know the Diameter: A = (π/4) × D2

or, when you know the Circumference: A = C2 / 4π

6 0
3 years ago
The table of values below represent an exponential function. Write an exponential equation that models the data. у 26 -2 -1 18.2
Gwar [14]

Answer:

I don't know actually because I dont know eng. very well

3 0
2 years ago
Select all of the domain values that would result in a denominator of zero for the equation
Oksi-84 [34.3K]

Answer:

Options (4) and (5)

Step-by-step explanation:

Given equation is,

\frac{x}{x-2}+\frac{1}{x-6}=\frac{4}{x^2-8x+12}

\frac{x(x-6)+(x-2)}{(x-2)(x-6)}=\frac{4}{x^2-8x+12}

\frac{x^2-5x-2}{(x-2)(x-6)}=\frac{4}{x^2-6x-2x+12}

\frac{x^2-5x-2}{(x-2)(x-6)}=\frac{4}{x(x-6)-2(x-6)}

\frac{x^2-5x-2}{(x-2)(x-6)}=\frac{4}{(x-2)(x-6)}

\frac{x^2-5x-2}{(x-2)(x-6)}-\frac{4}{(x-2)(x-6)}=0

\frac{x^2-5x-6}{(x-2)(x-6)}=0

Therefore, domain values that will result in a denominator of zero for the equation will be,

(x - 2) = 0 ⇒ x = 2

(x - 6) = 0 ⇒ x = 6

Therefore, options (4) and (5) will be the correct options.

5 0
4 years ago
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