Take half of the coefficient of x: It is 3, and half that is 3/2.
Then <span>x^2+3x=6 becomes:
</span><span> x^2+3x + (3/2)^2 =6 + (3/2)^2, and
(x+3/2)^2 = 6 + 9/4
You were not asked to solve the equation, but why not do it for the practice?
</span>Solve (x+3/2)^2 = 6 + 9/4 for x. There will be 2 values.
Y=5x-4
3y=15x-8
3(5x-4)=15x-8
15x-12=15x-8
??
Therefore, there is no solution.
Answer: the value of the account at the end of 6 years is is $8577
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = 6000
r = 6% = 6/100 = 0.06
n = 4 because it was compounded 4 times in a year.
t = 6 years
Therefore,.
A = 6000(1+0.06/4)^4 × 6
A = 6000(1+0.015)^24
A = 6000(1.015)^24
A = $8577
Step-by-step explanation:
this is a linear programming problem, and we are expected to draw up the linear program for the solution of the problem.
The objective function is
Maximize
35A+42B+20C=P
subject to constraints(board and wicker)
The constraints are
board
7A+5B+4C=3000
wicker
4A+5B+3C=1400
A>0, B>0, C>0
Answer:
Answer:
Distance is 13.6 units.
Which means it is 13
Step-by-step explanation:
Given a grid shows the positions of subway stop and house. The subway stop is located at (-7, 8) and house is located at (6, 4).
we have to find the distance between house and the subway stop.
Points are (-7, 8) and (6, 4).
Using distance formula,
D= /(x2-x1)^2+(y2-y1)^2} = (6-(-7))^2+(4-8)^2=(13)^2+16}={169+16}={185}=13.60147\sim13.6units.
Hence, distance between house and the subway stop is 13.6 units.