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I am Lyosha [343]
3 years ago
5

2. The sum of two numbers is 67 and their difference is 3. Find the two numbers.

Mathematics
1 answer:
nydimaria [60]3 years ago
3 0

Answer:

35 and 32

Step-by-step explanation:

35 and 32

because when we add 35 and 32 then their sum is 67

when we subtract 35 and 32 then their difference is 3

I hope u understand it

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Prove the divisibility of the following numbers:
Brut [27]

Answer:

Step-by-step explanation:

To prove divisibility, we need to factor the divident such that one of its factors matches the divisor.

(I use the notation x|y to denote that x divides y)

(A)

75^{30}|45^{45}\cdot15^{15}\\45^{45}\cdot15^{15}=3^{45}\cdot 15^{45}\cdot 15^{15}=\\=3^{45}\cdot 15^{60}=3^{45}\cdot 15^{30}\cdot 15^{30}=3^{45}\cdot (3\cdot5)^{30}\cdot 15^{30}=\\=3^{45}\cdot 3^{30}\cdot(5\cdot 15)^{30}=3^{45}\cdot 3^{30}\cdot(75)^{30}\\\implies\\75^{30}|3^{45}\cdot 3^{30}\cdot75^{30}

(B)

72^{63}|24^{54}\cdot 54^{24}\cdot2^{10}\\24^{54}\cdot 54^{24}\cdot2^{10}=(2^{162}\cdot 3^{54})\cdot(2^{24}\cdot 3^{72}) \cdot 2^{10}\\=2^{196}\cdot 3^{126}

In this case, it is easier to also factor the divisor to primes:

72^{63}=2^{189}\cdot 3^{126}

Both of these factor must be matched in the dividend in order to prove divisibility, and that indeed turns out to be true:

2^{189}\cdot 3^{126}|2^{196}\cdot 3^{126}\implies\\2^{189}|2^{196}\,\,\mbox{and}\,\,3^{126}|3^{126}

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3 years ago
For the following questions find the other half of the fraction.
valentina_108 [34]

Answer:

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<em>2</em><em>)</em><em> </em><em>3</em><em>/</em><em>6</em><em>=</em><em> </em><em>6</em><em>/</em><em>1</em><em>2</em>

<em>3</em><em>)</em><em> </em><em>4</em><em>/</em><em>1</em><em>0</em><em>=</em><em> </em><em>2</em><em>/</em><em>5</em>

<em>4</em><em>)</em><em> </em><em>3</em><em>/</em><em>4</em><em>=</em><em> </em><em>6</em><em>/</em><em>8</em>

<em>5</em><em>)</em><em> </em><em>5</em><em>/</em><em>1</em><em>0</em><em> </em><em>=</em><em> </em><em>1</em><em>/</em><em>2</em>

<em>6</em><em>)</em><em> </em><em>4</em><em>/</em><em>6</em><em>=</em><em> </em><em>8</em><em>/</em><em>1</em><em>2</em>

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S_A_V [24]

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Try this solution:
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