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Lynna [10]
3 years ago
10

A 13 foot ladder is resting against a house. The base of the ladder is 5 feet from the base of the wall.

Mathematics
1 answer:
Ugo [173]3 years ago
7 0

Answer:

This is just the application of Pythagoras theorem

To find how high up the wall the ladder reach

⇒ 13^2 = x^2 + 5^2

therefore x^2 = 13^2 - 5^2

                x^2 = 169 -25

                x^2 = 144

                   x = 12

therefore the ladder is 12 foot high up the wall

Step-by-step explanation:

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1. How far is KFC from RCBC Savings Bank? 2. How far is BaliwagLetchon Manok from RCBC Savings Bank? 3. How far is Baliwag Lecho
umka21 [38]

Answer:

Following are the solution to the given question.

Step-by-step explanation:

Please find the graph file and its solution in the attachment.  

4x-15=3x+28\\\\4x-3x=28+15\\\\x=43\\\\

Similarly:

3y+5=2y+50\\\\3y-2y=-5+50\\\\y=45\\\\

For point 1:\to KR=4x-15= 4\times 43-15=172-15=157

For point 2: \to BR=2y+50= 2\times 43+50=86+50=136

For point 3:\to BE=KR=157

For point 4:\to Kf=BR=130

For point 5:\to ERK=KFB=180^{\circ} -\angle B-\angle ERB = 180^{\circ}-92^{\circ}-18^{\circ}=70^{\circ}

4 0
3 years ago
A rectangle is placed around a semicircle as shown below. The length of the rectangle is 14mm. Find the area of the shaded regio
Damm [24]

Image is missing, so i have attached it

Answer:

21.07 mm²

Step-by-step explanation:

We will use the Formulas:

Area of semicircle = πr²/2

Area_rectangle = Length x width = Lw

We are given:

Length of rectangle = 14 mm

From the attached image, the diameter of the semicircle is equal to the length of the rectangle.

Thus;

diameter of semicircle = length of rectangle

Therefore,

diameter of semicircle = 14 mm

Also, from the attached image, the radius of the semicircle is equal to the width of the rectangle.

Thus;

diameter of semicircle/2 = radius of semicircle

Hence;

radius of semicircle = 14/2 = 7mm = width of rectangle

Thus;

Area of rectangle = L*w = 14 × 7 = 98 mm²

Area of semicircle = πr²/2 = π×7²/2 = 76.93 mm²

To get the area of the shaded region, we will subtract area of the semi-circle from the area of the rectangle.

Area of shaded region = Area_rectangle - Area_semicircle = 98 - 76.93 = 21.07 mm²

7 0
3 years ago
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