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Rasek [7]
3 years ago
8

A scientist digs up sample of arctic ice that is 458,000 years old. He takes it to his lab and finds that it contains 1.675 gram

s of krypton-81.
If the half-life of krypton-81 is 229,000 years, how much krypton-81 was present when the ice first formed?

Use the formula N = N0 .
Chemistry
1 answer:
Fiesta28 [93]3 years ago
3 0

Answer:

6.70 grams of krypton-81 was present when the ice first formed

Explanation:

Let use the below formula to find the amount of sample

N= N_0(\frac{1}{2})^n

where

n = \frac{t}{t_{\frac{1}{2}}}

here

t =  458,000 years

t_{\frac{1}{2}} = 229,000

\frac{t}{t_{\frac{1}{2}}} = \\frac{ 458,000}{229,000}

n = \frac{t}{t_{\frac{1}{2}}} = 2.000

Now substituting the values

1.675 = N_0(\frac{1}{2})^{2.000}}

1.675 = N_0\times (0.2500)

N_0= \frac{1.675}{0.2500}

N_0=6.70

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alexandr402 [8]

Answer:

A. The concentration of H+ is 0.0025 M

B. The pH is 2.6

C. The concentration of OH- is 3.98x10^-12 M

Explanation:

We'll begin by writing the balanced

dissociation equation of HClO4. This is illustrated below:

HClO4 —> H+ + ClO4-

A. Determination of the concentration of H+ in 0.0025 M HClO4. This is illustrated below:

From the balanced equation above,

1 mole of HClO4 produced 1 mole of H+.

Therefore, 0.0025 M of HClO4 will also produce 0.0025 M of H+.

The concentration of H+ is 0.0025 M

B. Determination of the pH.

The pH of the solution can be obtained as follow:

The concentration of H+, [H+]

= 0.0025 M

pH =?

pH = - log [H+]

pH = - log 0.0025

pH = 2.6

C. Determination of the concentration of OH-

To obtain the concentration of OH-, we must first calculate the pOH of the solution. This is illustrated below:

pH + pOH = 14

pH = 2.6

pOH =?

pH + pOH = 14

2.6 + pOH = 14

Collect like terms

pOH = 14 - 2.6

pOH = 11.4

Now, we can calculate the concentration of the OH- as follow:

pOH = - Log [OH-]

pOH = 11.4

11.4 = - Log [OH-]

- 11.4 = log [OH-]

[OH-] = anti log (- 11.4)

[OH-] = 3.98x10^-12 M

8 0
3 years ago
What was removed from the glucose molecules when they bonded to form maltose
steposvetlana [31]

Answer:

Two hydrogen atoms and one oxygen atom (water) was removed.

Explanation:

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5 0
3 years ago
I bet no one can solve this
Nikitich [7]
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3 years ago
What is the final concentration if 50.0 ml of a 2.00 m solution are diluted to 500.0 ml??
laila [671]
In order to calculate the final concentration of a dilution, it is important to memorise and remember the following equation:

C1V1/C2V2
Where: 
C1 = Initial concentration
V1 = Initial volume
C2 = Final concentration
V2 = Final volume

We are given three of the four, and we are asked to calculate the final concentration in moles, so we may substitute these given values into our equation as follows:

C1V1 = C2V2
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4 0
3 years ago
How many atoms of hydrogen are in 0.56 mol of (NH4)2SO4
BabaBlast [244]
<h2>Answer:2.7\times 10^{24} atoms</h2>

Explanation:

The given formula of the compound is (NH_{4})_{2}SO{4}

The formula says

Every mole of (NH_{4})_{2}SO{4} contains 8 moles of atoms of hydrogen.

Given that number of moles of compound is 0.56

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Since each mole has 6.022\times 10^{23} atoms,

4.48 moles has 4.48\times 6.022\times 10^{23}=2.7\times 10^{24} atoms.

7 0
3 years ago
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