The activity of pure substance is taken as 1 because it has no effect on the reaction. Hence the equilibrium constant of the reaction is given by: <span>Ka=[H3O+][HCO1−3]/[H2CO3]. Hope this helps :)</span>
Answer:
Gasoline isn't a pure substance.
Explanation:
A typical boiling range for gasoline is 100–400F. Gasoline has a vapor pressure of 7 psi in the summer, comparing it to water pressure it's less then 0.3 psi. For example if you spill water on a flat surface it might take a few minutes or hours to completly evapourate. Gasoline on the other hand it will evapurate within a few minutes, that's an example of volatility. Hope this helps
The chemical formula of the solute is NaNO3. The mass of this is 1.4*85=119 g. The boiling point of the solution is higher than water. The molarity of this solution is 1.4/2=0.7 M.
The answer to this would be helium
Answer:
m=621.54g
Explanation:
number of moles= mass of H2O/molar mass of H2O
n=m/mm
make mass the subject of the formula
m=n*mm
find molar mass of water
H2O=1(16)+2(1)
mm= 18.0g/mol. n=34.53mol
hence, m=34.53mol*18.0g/mol
m=621.54g