The absorbance reported by the defective instrument was 0.3933.
Absorbance A = - log₁₀ T
Tm = transmittance measured by spectrophotometer
Tm = 0.44
Absorbance reported in this equipment = -log₁₀ (0.44) = 0.35654
True absorbance can be calculated by true transmittance, Tm = T+S(α-T)
S = fraction of stray light = 6%= 6/100 = 0.06
α= 1, ideal case
T = true transmittance of the sample
Tm = T+S(α-T)
now, T= Tm-S/ 1-S = 0.44-0.06/ 1-0.06 = 0.404233
therefore, actual reading measured is A = -log₁₀ T = -log₁₀ (0.404233)
i.e; 0.3933
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Answer : The value of ΔG expressed in terms of F is, -1 F
Explanation :
First we have to calculate the standard electrode potential of the cell.

or,


Now we have to calculate the standard cell potential.
Formula used :

where,
= Gibbs free energy = ?
n = number of electrons = 2
F = Faraday constant
= standard e.m.f of cell = +0.5 V
Now put all the given values in this formula, we get the Gibbs free energy.


Therefore, the value of ΔG expressed in terms of F is, -1 F
The reaction is actually endothermic because delta H is positive, indicating that it absorbing heat.
75km/hr
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The Freezing point is ALWAYS the same as the melting point,even for different elements. 6,422 is its melting,and freezing point. Same with gold,iron,hydrogen,and many others