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3 years ago

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bob removed 24 fish for his pond over a period of 8 days. He removed the same number of fish each day what was the change in the

pond each day

2 answers:

makkiz [27]3 years ago

5 0

He removed 3 fish each day!

Anna [14]3 years ago

4 0

Answer:3

Step-by-step explanation:

24 fish divided by 8 days = 3 fish per day.

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Step-by-step explanation:

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(2x-3)(2x-3)

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(2x*2x) + (2x* -3) + (-3*2x) + (-3*-3)

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3 years ago

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Step-by-step explanation:

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3 years ago

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8x-5y=15 <br>6x+4y=43<br>solve the system by any method

Sedbober [7]

Answer:

$x=\frac{275}{62}$ , $y=\frac{127}{31}$

Step-by-step explanation:

<h3>I will use the elimination method.</h3>

We want to make the X's the same:

$24x-15y=45$

$24x+16y=172$

Because the signs of the X's are the same we subtract the 2 equations to make:

(I put the second one on top of the 1st)

$31y=127$

So:

$y=\frac{127}{31}$

Substitute y into either equation 1 or 2:

(I chose equation 1)

$8x-5(\frac{127}{31})=15$

$8x=5(\frac{127}{31}) + 15$

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So:

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2 years ago

Suppose that the ages of members in a large billiards league have a known standard deviation of σ = 12 σ=12sigma, equals, 12 yea

asambeis [7]

Answer:

$n\geq 23$

Step-by-step explanation:

-For a known standard deviation, the sample size for a desired margin of error is calculated using the formula:

$n\geq (\frac{z\sigma}{ME})^2$

Where:

$\sigma$ is the standard deviation
$ME$ is the desired margin of error.

We substitute our given values to calculate the sample size:

$n\geq (\frac{z\sigma}{ME})^2\\\\\geq (\frac{1.96\times 12}{5})^2\\\\\geq 22.13\approx23$

Hence, the smallest desired sample size is 23

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3 years ago