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elena-s [515]
3 years ago
10

bob removed 24 fish for his pond over a period of 8 days. He removed the same number of fish each day what was the change in the

pond each day
Mathematics
2 answers:
makkiz [27]3 years ago
5 0
He removed 3 fish each day!
Anna [14]3 years ago
4 0

Answer:3

Step-by-step explanation:

24 fish divided by 8 days = 3 fish per day.

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Which expressions are equivalent to 12x - 6? ​
iren2701 [21]
<h3>Answer</h3>

B and E

<h3>Explanation</h3>

A) It's wrong because

- 6 \times (2x - 1) =  - 12x + 6

B) It's right because

6 \times (2x - 1) = 12x - 6

C) It's wrong because

6x \times (2 - 1) = 6x \times 1 = 6x

D) It's wrong because

- 6x \times (2x - 1) =  - 12 {x}^{2} + 6

E) It's right because

- 6 \times ( - 2x + 1) = 12x - 6

F) It's wrong because

6 \times ( - 2x + 1) =  - 12x + 6

8 0
3 years ago
What is 2x+y=1 in slop intercept form?
Mekhanik [1.2K]

Answer: y = − 2 x + 1

This is because slope intercept from is "Y= mx+b" :)

5 0
3 years ago
Read 2 more answers
Please help me with this one!!
Tema [17]

Answer:

21 in^{2}

Step-by-step explanation:

The square in the middle has a length and width of 3, so multiply. <u>9</u>.

All of the triangles have a base of 3 and a height of 2. The area equation for triangles is

A=bh\frac{1}{2}

So base*height is 6. Divide that by 2 or multiply by 1/2.

You get 3. There are 4 triangles, so multiply <em>that</em> by 4. <u>12</u>.

Add 12 and 9 together, and you get:

21 in^{2}

I hope this helps!

6 0
3 years ago
Can someone please help me?
melamori03 [73]

Answer:

Answer is B

Step-by-step explanation:

3 0
2 years ago
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Which matrix represents the system of equations shown below? 2x-y=-6 and x-6y=13​
dezoksy [38]

Answer: D

<u>Step-by-step explanation:</u>

The first matrix contains the coefficients of the x- and y- values for both equations (top row is the top equation and the bottom row is the bottom equation. The second matrix contains what each equation is equal to.

\begin{array}{c}2x-y\\x-6y\end{array}\qquad \rightarrow \qquad \left[\begin{array}{cc}2&-1\\1&-6\end{array}\right] \\\\\\\begin{array}{c}-6\\13\end{array}\qquad \rightarrow \qquad \left[\begin{array}{c}-6\\13\end{array}\right]

The product will result in the solution for the x- and y-values of the system.

6 0
3 years ago
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