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lina2011 [118]
3 years ago
5

Which matrix represents the system of equations shown below? 2x-y=-6 and x-6y=13​

Mathematics
1 answer:
dezoksy [38]3 years ago
6 0

Answer: D

<u>Step-by-step explanation:</u>

The first matrix contains the coefficients of the x- and y- values for both equations (top row is the top equation and the bottom row is the bottom equation. The second matrix contains what each equation is equal to.

\begin{array}{c}2x-y\\x-6y\end{array}\qquad \rightarrow \qquad \left[\begin{array}{cc}2&-1\\1&-6\end{array}\right] \\\\\\\begin{array}{c}-6\\13\end{array}\qquad \rightarrow \qquad \left[\begin{array}{c}-6\\13\end{array}\right]

The product will result in the solution for the x- and y-values of the system.

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EleoNora [17]

Answer:

no

Step-by-step explanation:

I goo.g.led, sorry me dum lol

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3 years ago
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Which polynomial can be simplified to a difference of squares
Mrrafil [7]
<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}=(4-1)(4+1)

<h2>Why?</h2>

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

So,

Discarding, we have:

The quadratic terms of the given polynomials are:

First=10a^{2}

Second=16a^{2}

Third=25a^{2}

Fourth=24a^{2}

We have that the coefficients of the quadratic terms that can be obtained by squaring are:

16a^{2} =(4a)^{2} \\\\25a^{2} =(5a)^{2}

The other two coefficients are not perfect squares since they can not be obtained by square rooting whole numbers.

So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.

Therefore, we need to work with the second and the third polynomial.

For the second polynomial, we have:

16a^{2} -4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2} =(4-1)(4+1)

So, the second polynomial can be simplified to a difference of squares.

For the third polynomial, we have:

25a^{2} +6a-6a+36=16a^{2}+36=(5a)^{2}+(6)^{2}

So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.

Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}

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3 years ago
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I’m pretty confused on this question. Anyone know the answers?
Afina-wow [57]

Answer:

see explanation

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

• If m > 0, then the line slopes upwards from left to right ( increases )

• If m < 0, then the line slopes downwards from left to right ( decreases )

(a)

y + x = 3 ( subtract x from both sides )

y = - x + 3 ← in slope-intercept form

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y = 4x + 8 ← is in slope-intercept form

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x - 5 = 0 ( add 5 to both sides )

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3 years ago
(50 POINTS) Math Inverse Functions please help
Afina-wow [57]

Answer:

See below.

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The inverse function has these ordered pairs:

(3, 1), (4, 7), (6, 8), (y, 9)

For a relation to be a function, a value used as an x-coordinate can appear only once.

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