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lina2011 [118]
4 years ago
5

Which matrix represents the system of equations shown below? 2x-y=-6 and x-6y=13​

Mathematics
1 answer:
dezoksy [38]4 years ago
6 0

Answer: D

<u>Step-by-step explanation:</u>

The first matrix contains the coefficients of the x- and y- values for both equations (top row is the top equation and the bottom row is the bottom equation. The second matrix contains what each equation is equal to.

\begin{array}{c}2x-y\\x-6y\end{array}\qquad \rightarrow \qquad \left[\begin{array}{cc}2&-1\\1&-6\end{array}\right] \\\\\\\begin{array}{c}-6\\13\end{array}\qquad \rightarrow \qquad \left[\begin{array}{c}-6\\13\end{array}\right]

The product will result in the solution for the x- and y-values of the system.

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Answer:

2,4

Step-by-step explanation:

They are the only two prime numbers

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3 years ago
8. Combine the like terms in this expression: –3x + 2xy + 4y – xy + 2x – 11y
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Answer:

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Step-by-step explanation:

We just have to combine (add) the similar terms... so all terms that have an x in them for example.

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Let's first re-write it placing similar terms next to each other

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4 years ago
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padilas [110]
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Digiron [165]

Answer:

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So, the probability of getting the first marble shaded = \frac{\binom{4}{1}}{\binom{11}{1}} = \frac{4}{11}

Also, there are 6 odd labeled marbles.

So, the probability of getting the second marble being odd labeled = \frac{\binom{6}{1}}{\binom{11}{1}} = \frac{6}{11}

So, the probability of getting the first marble shaded and second marble labeled odd = \frac{4}{11}\times \frac{6}{11} = \frac{24}{121}.

Hence, the required probability is \frac{24}{121}.

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