Write 7,000,000+300,000+ 40,000+ 5,000+ 800+ 2 in word form
2 answers:
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Answer:
The lifetime value needed is 11.8225 hours.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.
In this problem, we have that:
The lifetime of a certain type of battery is normally distributed with mean value 11 hours and standard deviation 1 hour. This means that .
What lifetime value is such that the total lifetime of all batteries in a package exceeds that value for only 5% of all packages?
This is the value of THE MEAN SAMPLE X when Z has a pvalue of 0.95. That is between Z = 1.64 and Z = 1.65. So we use
Since we need the mean sample, we need to find the standard deviation of the sample, that is:
So:
The lifetime value needed is 11.8225 hours.
<h3>Answer:</h3>
The rules of exponents tell you ...
... (a^b)(a^c) = a^(b+c) . . . . . . applies inside parentheses
... (a^b)^c = a^(b·c) . . . . . . . . applies to the overall expression
The Order of Operations tells you to evaluate inside parentheses first. Doing that, you have ...
... x^(4/3)·x^(2/3) = x^((4+2)/3) = x^2
Now, you have ...
... (x^2)^(1/3)
and the rule of exponents tells you to multiply the exponents.
... = x^(2·1/3) = x^(2/3)