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wlad13 [49]
3 years ago
11

Find three consecutive even numbers whose sum is 1884.

Mathematics
1 answer:
Scilla [17]3 years ago
5 0

Answer:

smallest number=626

middle number=628

larger number=630

Step-by-step explanation:

To find the numbers, let's use n as the variable. Since we know that the numbers are consecutive even numbers, we know that they increase by 2. For example, we could have 2+4+6=12.

Knowing that the consecutive numbers increase by two's, we can use this.

smallest number: n

middle number: n+2

larger number: n+4

All we have to do is add these together and set it equal to 1884.

n+(n+2)+(n+4)=1884          [combine like terms]

3n+6=1884                         [subtract both sides by 6]

3n=1878                              [divide both sides by 3]

n=626

Now that we know n=626, we also know that the other numbers are 626, 628, 630 respectively.

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White raven [17]
The sum of the polynomials (8x²-9y²-4x)+(x²-3y²<span>-7x) is:

 1. You must add the terms whose variables and exponents are the same. 
 2. Let's rewrite the polynomials:
</span>
 (8x²-9y²-4x)+(x²-3y²-7x)
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 3. Therefore, the result is:

 9x²-11x-12y²

 3. <span>What is the sum of the polynomials?

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3 years ago
Suppose the ice Q scores in one region are normally distributed within a standard deviation of 13. Suppose also that exactly 51%
elena-14-01-66 [18.8K]

Answer:

z=-0.025

And if we solve for \mu we got

\mu=100 +0.025*13=100.325

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu,13)  

Where \mu=? and \sigma=13

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

For this case we know these conditions:

P(X>100)=0.51   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.49 of the area on the left and 0.51 of the area on the right it's z=-0.025. On this case P(Z<-0.025)=0.49 and P(z>-0.025)=0.51

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-0.025

And if we solve for \mu we got

\mu=100 +0.025*13=100.325

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Step-by-step explanation:

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