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wlad13 [49]
3 years ago
11

Find three consecutive even numbers whose sum is 1884.

Mathematics
1 answer:
Scilla [17]3 years ago
5 0

Answer:

smallest number=626

middle number=628

larger number=630

Step-by-step explanation:

To find the numbers, let's use n as the variable. Since we know that the numbers are consecutive even numbers, we know that they increase by 2. For example, we could have 2+4+6=12.

Knowing that the consecutive numbers increase by two's, we can use this.

smallest number: n

middle number: n+2

larger number: n+4

All we have to do is add these together and set it equal to 1884.

n+(n+2)+(n+4)=1884          [combine like terms]

3n+6=1884                         [subtract both sides by 6]

3n=1878                              [divide both sides by 3]

n=626

Now that we know n=626, we also know that the other numbers are 626, 628, 630 respectively.

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5^2x=28 <br> (Help me please!!!!!!)
gizmo_the_mogwai [7]
Okay so i would do this with a logarithm. 
5^(2x) = 28 
take the log of both sides
log5^(2x) = log28   and because of this log rule: logA^n = nlogA 
(2x)log5= log28
then divide by log5 on both sides
2x = log28 / log5
and divide by 2
x = (log28 / log5) /2
this can be found with a calculator:

x= about 1.03521...
round that to whatever the question says to
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2 years ago
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