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Murljashka [212]
3 years ago
5

Examples of electromagnetic wave

Chemistry
1 answer:
dlinn [17]3 years ago
3 0

Answer:

Believe it or not our the light we see "visible light" is an example of electromagnetic wave. other examples include microwaves, radio waves, infrared, ultraviolet, x-rays, and gamma rays.

Explanation:

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HELP!!!! ASAP!!!!!!!!!!<br><br> HOW ARE REACTANTS DIFFERENT FROM THE PRODUCTS ?
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Reactants are what make up the product.
7 0
4 years ago
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N2 + 3H2 → 2NH3 How many moles of hydrogen are needed to react with 5 moles of nitrogen?​
Sonbull [250]

Answer:

6 MOLES

YES MATES! TWO MOLES OF N2 REQIURS 6 MOLES OF H2 GASE TO REACT COMPLETLY

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3 years ago
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A 3.0 L cointainer contains 4 mol He, 2 mol Ne,and 1 mol Ar. What is the mole fraction of neon gas? What is the partial pressure
CaHeK987 [17]

Answer:

Partial pressure of Ne = 1.43 atm

Explanation:

Step 1: Data given

Volume = 3.0 L

Number of moles He = 4 moles

Number of moles Ne = 2 moles

Number of moles Ar = 1 mol

Total pressure = 5 atm

Step 2: Calculate total moles

Total moles = 4 moles + 2 moles + 1 mol

Total moles = 7 moles

Step 3: Calculate the mol ratio

Mol ratio = moles / total mol

Mol ratio He = 4 moles / 7 moles = 0.571

Mol ratio Ne = 2 moles / 7 moles = 0.286

Mol ratio Ar = 1 mol / 7 moles = 0.143 moles

Ste p4: Calculate partial pressure

PArtial pressure = mol ratio * total pressure

Partial pressure of Ne = mol ratio Ne * total pressure

Partial pressure of Ne = 0.286 * 5 atm

Partial pressure of Ne = 1.43 atm

8 0
3 years ago
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If 55.8 ml of bacl2 solution is needed to precipitate all the sulfate ion in a 742 mg sample of na2so4, what is the molarity of
lukranit [14]

Answer is: the molarity of the solution is 0.0936 M.

Balanced chemical reaction: BaCl₂(aq) + Na₂SO₄(aq) → BaSO₄(s) + 2NaCl(aq).

Net ionic reaction: Ba²⁺ + SO₄²⁻ → BaSO₄(s).

V(BaCl₂) = 55.8 mL; volume of barium chloride solution.

V(BaCl₂) = 55.8 mL ÷ 1000 mL/L = 0.0558 L.

m(Na₂SO₄) = 742 mg ÷ 1000 mg/g.

m(Na₂SO₄) = 0.742 g; mass of sodium sulfate.

n(Na₂SO₄) = m(Na₂SO₄) ÷ M(Na₂SO₄).

n(Na₂SO₄) = 0.742 g ÷ 142.04 g/mol.

n(Na₂SO₄) = 0.00522 mol; amount of substance.

From chemical reaction: n(Na₂SO₄) : n(BaCl₂) = 1 : 1.

n(BaCl₂) = 0.00522 mol.

c(BaCl₂) = n(BaCl₂) ÷ V(BaCl₂).

c(BaCl₂) = 0.00522 mol ÷ 0.0558 L.

c(BaCl₂) = 0.0936 M.

3 0
3 years ago
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