Moles= mass/Mr
Moles= 3.82/40
Moles= 0.0955 mol
Consider the amount of energy needed to brake the bonds.
In c=o there are both a pi-bond and a sigma bond. Therefore it requires a higher energy to brake it. When considering the c-o bond there is only a single sigma bond is needed to be broken. Therefore braking is easier.
When something is easily broken they are having a weak attraction. When they harder to break they are having a stronger attraction.
Here weak attraction is having a lower energy while stronger attraction has higher energy.
Therefore c=o provides a high energy than c-o
Answer:
Manganese decreases from 4+ to 2+ (reduced and oxidizing agent) and nitrogen increases from 2+ to 5+ (oxidized and reducing agent).
Explanation:
Hello there!
In this case, according to the given redox reaction, we rewrite it as a convenient first step:

Next, we assign the oxidation numbers as follows:

Thus, we can see that both manganese and nitrogen undergo a change in their oxidation number, the former decreases from 4+ to 2+ (reduced and oxidizing agent) and the latter increases from 2+ to 5+ (oxidized and reducing agent).
Regards!
Hydrogen + oxygen --> water
59,1g + x = 528g
528g - 59,1 = x
x = 468,9g