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NARA [144]
3 years ago
6

Please solve. best answer gets rewarded! show step by step.

Mathematics
2 answers:
Mrrafil [7]3 years ago
6 0
2x-4-5x=2
2x -5x= -3x
 -4-3x= 2
+4       +4
------------
     -3x = 6
 ------------------
       -3    -3
        
       x = -2
sukhopar [10]3 years ago
4 0
Hey!

Let's write the problem.
2x-4-5x=2
Add like terms...
-3x-4=2
Add 4 to both sides.
-3x-4+4=2+4
-3x=6
Divide both sides by -3.
\frac{-3x}{-3}=\frac{6}{-3}

Our final answer would be,
x=-2

Thanks!
-TetraFish
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<h3>Why isn’t a good idea to study in bed?</h3>

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5 0
3 years ago
Read 2 more answers
A box contains 5 red and 5 blue marbles. Two marbles are withdrawn randomly. If they are the same color, then you win $1.10; if
topjm [15]

Answer:

a) The expected value is \frac{-1}{15}

b) The variance is  \frac{49}{45}

Step-by-step explanation:

We can assume that both marbles are withdrawn at the same time. We will define the probability as follows

#events of interest/total number of events.

We have 10 marbles in total. The number of different ways in which we can withdrawn 2 marbles out of 10 is \binom{10}{2}.

Consider the case in which we choose two of the same color. That is, out of 5, we pick 2. The different ways of choosing 2 out of 5 is \binom{5}{2}. Since we have 2 colors, we can either choose 2 of them blue or 2 of the red, so the total number of ways of choosing is just the double.

Consider the case in which we choose one of each color. Then, out of 5 we pick 1. So, the total number of ways in which we pick 1 of each color is \binom{5}{1}\cdot \binom{5}{1}. So, we define the following probabilities.

Probability of winning: \frac{2\binom{5}{2}}{\binom{10}{2}}= \frac{4}{9}

Probability of losing \frac{(\binom{5}{1})^2}{\binom{10}{2}}\frac{5}{9}

Let X be the expected value of the amount you can win. Then,

E(X) = 1.10*probability of winning - 1 probability of losing =1.10\cdot  \frac{4}{9}-\frac{5}{9}=\frac{-1}{15}

Consider the expected value of the square of the amount you can win, Then

E(X^2) = (1.10^2)*probability of winning + probability of losing =1.10^2\cdot  \frac{4}{9}+\frac{5}{9}=\frac{82}{75}

We will use the following formula

Var(X) = E(X^2)-E(X)^2

Thus

Var(X) = \frac{82}{75}-(\frac{-1}{15})^2 = \frac{49}{45}

7 0
4 years ago
Help pls!!!! And I will give pizza forever!!!
SOVA2 [1]
The number of red  beads are increasing by 2  for each new pattern
The next number of reds will be 12.  ( in patern 5)

number of blue beads in pattern 5 will be 15 ( increasing by 3 )

nth term for red  = 4 + 2 (n-1)  ( its an arithmetic sequence)

nth term for blue =  3 + 3(n - 1)   - as above ,arithmetic.

Total beads in pattern 45 is

No. red beads in pattern 26   = 4  + 2(26-1)  = 4 + 50 = 54
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Total number of beads in pattern 45 is:-

 4 + 2(44) + 3 + 3(44)  =   227 


7 0
3 years ago
Help pleaseeeeeee and good morning
dimulka [17.4K]

Answer:

1a w=-9                 1b s=20/7

2a x=12                 2b v=11

3a b=10                 3b a=9/5

4a c=1                    4b x=2

Step-by-step explanation:

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Verdich [7]
Be more specific with the question that you’re asking bc I will love to help
3 0
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