Question

what is the greatest 5 digit number which when divided by 2, 3, 4, and 5 leaves a remainder of 1 in each case​

Answer 1

Answer:99904.

Step-by-step explanation:

Find the LCM of

5

10 = 2x5

15 = 3x5

20 = 2x2x5

25 = 5x5

LCM = 2x2x3x5x5 = 300

Take the smallest 5-digit number: 10000 and divide it by 300 to get 33.33. Round it off to 34 and multiply it by 300 to get 10200. Finally add 4 to 10200 to get 10204 which is the smallest final 5-digit number.

Check: 10204/5 = 2040 as quotient and a remainder of 4. Correct.

10204/10 = 1020 as quotient and a remainder of 4. Correct.

10204/15 = 680 as quotient and a remainder of 4. Correct.

10204/20 = 510 as quotient and a remainder of 4. Correct.

10204/25 = 408 as quotient and a remainder of 4. Correct.

Answer: 10204.

To get the greatest 5-digit number take 99999 and divide it by 300 to get 333.33. Round it off to 333 and multiply it by 300 to get 99900. Finally add 4 to 99900 to get 99904 which is the final greatest 5-digit number.

Check: 99904/5 = 19980 as quotient and a remainder of 4. Correct.

99904/10 = 9990 as quotient and a remainder of 4. Correct.

99904/15 = 6660 as quotient and a remainder of 4. Correct.

99904/20 = 4995 as quotient and a remainder of 4. Correct.

99904/25 = 3996 as quotient and a remainder of 4. Correct.

Answer: 99904.