Which subset of real numbers does not contain the number 1?

Katyanochek1 [597]

You just put it in a fraction 1/10

4 0

2 years ago

Im not sure how to do this or what function to use SIN, COS, or TAN but if you could walk me through it that would be so so so a

Elanso [62]

Answer: 3.8

Step-by-step explanation:first, you need to figure out what side you’re looking for. Side AC is opposite of the angle you’re given. They also give you length of side AB which is 4. That is the hypotenuse (side directly across from right angle). So, you have the hypotenuse, and need the find the opposite side measure. Which option uses opposite and hypotenuse? That’s Sin. So, you would do: sin70 = ? / 4.

sin (of given angle)= opposite / hypotenuse.

Sin (70 degrees) = ? / 4

Then you solve for “?”

Type sin70 into your calculator, then multiply both sides by 4 to get “?” by itself. You should get 3.758770483, which rounds to 3.8

5 0

2 years ago

If you answer all the questions you get brainliest

Triss [41]

The ans is the one with G'(-6,0)

7 0

3 years ago

A doctor released the results of clinical trials for a vaccine to prevent a particular disease. In these clinical trials, 200,0

CaHeK987 [17]

Answer:

1) No, there is not enough evidence to support the claim that the vaccine was effective (P-value=0.104) .

The null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0$

being the subindex 1 for the experimental group and subindex 2 for the control group.

2) Test statistic z=-1.26

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the vaccine was effective.

Then, the null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0$

The significance level is 0.01.

The sample 1 (experimental group), of size n1=100000 has a proportion of p1=0.0002.

$p_1=X_1/n_1=21/100000=0.0002$

The sample 2 (control group), of size n2=100000 has a proportion of p2=0.0003.

$p_2=X_2/n_2=30/100000=0.0003$

The difference between proportions is (p1-p2)=-0.0001.

$p_d=p_1-p_2=0.0002-0.0003=-0.0001$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{21+30}{100000+100000}=\dfrac{51}{200000}=0.00026$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.00026*0.99974}{100000}+\dfrac{0.00026*0.99974}{100000}}\\\\\\s_{p1-p2}=\sqrt{0+0.0000000025}=\sqrt{0.0000000051}=0.000071$