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3 years ago

Which subset of real numbers does not contain the number 1?

Mathematics

1 answer:

Leni [432]3 years ago

5 0

Answer:

I think the answer might be c or b.I hope this helps

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The angle θ 1 is located in Quadrant IV, and cos ⁡ ( θ 1 ) = 9/ 19 , theta, start subscript, 1, end subscript, right parenthesis

Firdavs [7]

Answer:

$sin\theta_1 = - \frac{2\sqrt{70}}{19}$

Step-by-step explanation:

We are given that $\theta_1$ is in <em>fourth</em> quadrant.

$cos\theta_1$ is always positive in 4th quadrant and

$sin\theta_1$ is always negative in 4th quadrant.

Also, we know the following identity about $sin\theta$ and $cos\theta$ :

$sin^2\theta + cos^2\theta = 1$

Using \theta_1 in place of \theta:

$sin^2\theta_1 + cos^2\theta_1 = 1$

We are given that $cos\theta_1 = \frac{9}{19}$

$\Rightarrow sin^2\theta_1 + \dfrac{9^2}{19^2} = 1\\\Rightarrow sin^2\theta_1 = 1 - \dfrac{81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{280}{361}\\\Rightarrow sin\theta_1 = \sqrt{\dfrac{280}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{2\sqrt{70}}{19}, -\dfrac{2\sqrt{70}}{19}$

$\theta_1$ is in <em>4th quadrant </em>so $sin\theta_1$ is negative.

So, value of $sin\theta_1 = - \frac{2\sqrt{70}}{19}$

6 0

3 years ago

Difference

Ivan

Answer:

The value of a function is the actual calculation done at a certain point. The limit is - roughly speaking - the value at points that are “arbitrarily close” to the same point. For most commonly used functions, the value of a function at a point, and the limit at the same point, is the same - at least for most values.

4 0

2 years ago

On a standard circular 12-hour clock, the numerals 12 and 6 are opposite each other. On the planet Bajor, they use a circular te

anastassius [24]

Opposite Numbers and their Sums:

1+6=7
2+7=9
3+8=11
4+9=13
5+10=15

Because of this, the pair of opposite numbers are 3 and 8 if you want the pair that equal 11.

7 0

3 years ago

A car goes from rest to 50 m/s in 5 seconds. What is the acceleration?

AVprozaik [17]

The acceleration is 10 because 50 divided by 5 is 10.

3 0

3 years ago

59. What happens to the graph of y = |x| when the equation changes to y = |x + 4? A The graph shifts up 4 units. The graph shift

marishachu [46]

Answer: Graph shifts 4 units to the left

Explanation:

I'm assuming you meant to say y = |x+4|

If so, then the graph shifts 4 units to the left. Replacing x with x+4 moves the xy axis 4 units to the right if we held the V shape in place (since each x is now 4 units larger). This gives the illusion the V shape is moving 4 units to the left.

Or you could look at the vertex point to see how it moves. On y = |x|, the vertex is at (0,0). It then moves to (-4,0) when we go to y = |x+4|

8 0

3 years ago