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3 years ago

13

Jeffrey purchase and download 12 songs on Monday he purchase an additional 3 songs on Tuesday the cost to download each song is

$2 write a numeral expression to represent the situation

1 answer:

bonufazy [111]3 years ago

4 0

(12x3)+(3x2) Because on Monday he bought 12 songs for $3 each and on Tuesday he bought 2 songs for $3 each.

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What kind of problems could be solved with GCF and LCM

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3 years ago

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The sales tax on a $24 model rocket is $1.92 what is the percent of sales tax

AleksAgata [21]

Input data

Price model rocket = $24

Tax = $1.92

What is the percent of sales tax?

Procedure

r = percent of sales tax

$r=\frac{1.92}{24}=0.08=8\text{ \%}$

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1 year ago

Sam ran 3 1/2 miles in 25 minutes. If he continues running at this pace how far will he run in 1 hour

zheka24 [161]

Answer: 8.4 or 8 2/5

Step-by-step explanation:

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2 years ago

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A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

3 years ago

If 3/4=x/2 then 7/4=

wariber [46]

I don’t know

I need to answer a question I'm new sorry

8 0

3 years ago