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d1i1m1o1n [39]
3 years ago
7

Which equation does not represent a linear function of x ?

Mathematics
2 answers:
KatRina [158]3 years ago
7 0
The\ linear\ function\ represent\ an\ equations:\\\\y=mx+b;\ Ax+By=C;\ Ax+Bx+C=0

therefore:\\A)\ y=2x^3-3\to\boxed{NO}\\\\B)\ y=\frac{4}{3}x\to\boxed{YES}\to y=mx+b\\\\C)\ y=\frac{x}{4}=\frac{1}{4}x\to\boxed{YES}\to y=mx+b
hichkok12 [17]3 years ago
6 0
Y=2x³-3 
Any equation where the x is squared or cubed would make a curve on a graph. :)
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explaination: math
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3 years ago
A simple random sample of size n=14 is obtained from a population with μ=64 and σ=19.
madam [21]

Answer:

a) A. The population must be normally distributed

b) P(X < 68.2) = 0.7967

c) P(X  ≥  65.6) = 0.3745

Step-by-step explanation:

a) The population is normally distributed having a mean (\mu_x) = 64  and a standard deviation (\sigma_x) = \frac{19}{\sqrt{14} }

b) P(X < 68.2)

First me need to calculate the z score (z). This is given by the equation:

z=\frac{x-\mu_x}{\sigma_x} but μ=64 and σ=19 and n=14,  \mu_x=\mu=64 and \sigma_x=\frac{ \sigma}{\sqrt{n} }=\frac{19}{\sqrt{14} }

Therefore: z=\frac{68.2-64}{\frac{19}{\sqrt{14} } }=0.83

From z table, P(X < 68.2) = P(z < 0.83) = 0.7967

P(X < 68.2) = 0.7967

c) P(X  ≥  65.6)

First me need to calculate the z score (z). This is given by the equation:

z=\frac{x-\mu_x}{\sigma_x}

Therefore: z=\frac{65.6-64}{\frac{19}{\sqrt{14} } }=0.32

From z table,  P(X  ≥  65.6) =  P(z  ≥  0.32) = 1 -  P(z  <  0.32) = 1 - 0.6255 = 0.3745

P(X  ≥  65.6) = 0.3745

P(X < 68.2) = 0.7967

5 0
3 years ago
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svp [43]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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