Question

Find the equation of the line in standard form containing a point P(-3, 3) and a slope m = -4/3

Answer 1

Answer:

4x + 3y = -3.

Step-by-step explanation:

Using the point-slope form of  a straight line:

y - y1 = m(x - x1)

y - 3 = -4/3(x - (-3))

y - 3 = -4/3x - 4

4/3x + y = -4 + 3 = -1

Multiply through by 3:-

4x + 3y = -3.

Answer 2

Answer:

4x+3y+3=0

Step-by-step explanation:

Equation of a line containing a point (x1,y1),

and a slope m is given by,

(y-y1)=m(x-x1)

Here, x1= -3 , y1= 3 , m= -4/3

Putting the values,

(y-3)=-4/3(x+3)

or,3(y-3)=-4(x+3)

or,3y-9=-4x-12

or,4x+3y+3=0 , is the required equation.