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mr Goodwill [35]
3 years ago
6

Find the equation of the line in standard form containing a point P(-3, 3) and a slope m = -4/3

Mathematics
2 answers:
Kipish [7]3 years ago
8 0

Answer:

4x + 3y = -3.

Step-by-step explanation:

Using the point-slope form of  a straight line:

y - y1 = m(x - x1)

y - 3 = -4/3(x - (-3))

y - 3 = -4/3x - 4

4/3x + y = -4 + 3 = -1

Multiply through by 3:-

4x + 3y = -3.

Ghella [55]3 years ago
6 0

Answer:

4x+3y+3=0

Step-by-step explanation:

Equation of a line containing a point (x1,y1),

and a slope m is given by,

(y-y1)=m(x-x1)

Here, x1= -3 , y1= 3 , m= -4/3

Putting the values,

(y-3)=-4/3(x+3)

or,3(y-3)=-4(x+3)

or,3y-9=-4x-12

or,4x+3y+3=0 , is the required equation.

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If quadrilateral MNPO is reflected over the x-axis, what are the coordinates of
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<em>Note: you have not added the image, so I am assuming the quadrilateral MNOP with coordinates M(-4, 0), N(5, -3), P(2, 6) and O(-5, 7). It will anyhow clear your concept as I would explain the concept of reflection over the x-axis.</em>

Step-by-step explanation:

Considering the quadrilateral MNPO with assumed vertices

  • <em>M(-4, 0)</em>
  • <em>N(5, -3)</em>
  • <em>P(2, 6)</em>
  • <em>O(-5, 7)</em>

<em />

<em>THE RULE OF REFLECTION </em>states that when we tend to reflect a point let say (x, y), across the x-axis, the x-coordinate does not change or transform, but the y-coordinate is changed into its opposite sign i.e. (x,-y).

So, the coordinates of the point in the image after quadrilateral MNPO is reflected over the x-axis will be:

<h3>(x, y)                      (x, -y)</h3>

<em>M(-4, 0)                     M'(-4, 0)</em>

<em>N(5, -3)                     N'(5, 3)</em>

<em>P(2, 6)                      P'(2, -6)</em>

<em>O(-5, 7)                   O'(-5, -7)</em>

Hope, it will help you clear your concept regarding reflection of an object over the x-axis. Using this understanding, you can solve any other question related to this topic.

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