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2 years ago

8

∠ABD is formed by a tangent and a secant intersecting outside of a circle. If minor arc AC = 72° and minor arc CD = 132°, what i

s the measure of ∠ABD?

2 answers:

romanna [79]2 years ago

7 0

Answer: 42°

Step-by-step explanation:

First, find the minor arc AD.

arc AD=360-72-123=156

Then, ∆ABD=1/2(minor arc AD- minor arc AC)

∆ABD=1/2 (156-72)

∆ABC=1/2 84

∆ABC=42°

Sonbull [250]2 years ago

5 0

Check the picture below

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2 years ago

Help me with #5 pleaseeeeeeeeeee

earnstyle [38]

Answer:

$\angle 1 = 45$ degrees

Step-by-step explanation:

Sum of 3 angles in a triangle is 180..

The angles given are:

60

7x + 12

1

So we sum to 180 and write:

$60+7x+12+\angle 1=180\\72+7x+\angle 1=180\\7x+\angle 1=108$

Also, straight angle is 180 degrees, thus Angle 1 and (14x + 9) angle is sum to 180, thus we can write:

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Or we can write this as:

$14x + \angle 1=171\\\angle 1 = 171 - 14x$

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6 0

2 years ago

A girl scout troop sold cookies. If the girls sold 5 more boxes the second week than they did the first, and if they double the

valina [46]

Answer:

Boxes sold first week = 104

Boxes sold second week =x+5= 104+5=109

Boxes sold third week = 109 times 2= 218

Step-by-step explanation:

Let x be the number of boxes sold in first week

the girls sold 5 more boxes the second week

So number of boxes sold in second week is x+5

they double the sales of the second week for the third week

So number of boxes sold in third week is 2 (x+5)

Total boxes sold is 431

$x+x+5+2(x+5)=431$

$x+x+5+2x+10=431$

$4x+15=431$

subtract 15 from both sides

$4x=416$

divide by 4 on both sides

$x=104$

Boxes sold first week = 104

Boxes sold second week =x+5= 104+5=109

Boxes sold third week = 104 times 2= 218

4 0

3 years ago