Answer:
15 seconds
Step-by-step explanation:
If you make a table of values for the dog and the squirrel using d = rt, then the rates are easy: the dog's rate is 150 and the squirrel's is 100. The t is what we are looking for, so that's our unknown, and the distance is a bit tricky, but let's look at what we know: the dog is 200 feet behind the squirrel, so when the dog catches up to the squirrel, he has run some distance d plus the 200 feet to catch up. Since we don't know what d is, we will just call it d! Now it seems as though we have 2 unknowns which is a problem. However, if we solve both equations (the one for the dog and the one for the squirrel) for t, we can set them equal to each other. Here's the dog's equation:
d = rt
d+200 = 150t
And the squirrel's:
d = 100t
If we solve both for t and set them equal to each other we have:

Now we can cross multiply to solve for d:
150d = 100d + 20,000 and
50d = 20,000
d = 400
But we're not looking for the distance the squirrel traveled before the dog caught it, we are looking for how long it took. So sub that d value back into one of the equations we have solved for t and do the math:

That's 1/4 of a minute which is 15 seconds.
Hi!
First of all, we can look and see that these sqaure roots are the same, so it's easy to add.
In square roots, if the number INSIDE the square root is the same, it stays that way for the answer .
So the equation is 9(square root) 5 + 4(square root) 5.
The numbers out the sqaure root can just be added. So 9+4 = 13.
Lastly just attach the sqaure root onto the 13
Final answer should be 13(square root)5
***use the actual symbol in place of (sqaure root)
I hope this helps!
That is the correct answer
Exact form 17/4
decimal form 4.25
mixed number form 4 1/4
math way is your friend