All categories

4 years ago

The slope of the line

Mathematics

1 answer:

erica [24]4 years ago

8 0

The slope of the line is -1

And the linear equations is y= -1x-4

I hope this helps you can you rate my answer thank you

You might be interested in

-40 greater than or equal to 8b

viva [34]

- 40 ≥ 8 b

switch sides:

8b ≤ - 40

divide both sides by 8 :

8b / 8 = - 40/8

refine:

b ≤ - 40 / 8

b ≤ - 5

hope this helps!

7 0

3 years ago

For the limit

slava [35]

Gxdsudusujssuduydtehd

4 0

3 years ago

The null and alternative hypotheses are given. Determine whether the hypothesis test is left-tailed, right-tailed, or two-tail

Rainbow [258]

Answer:

The hypothesis test is right-tailed and the parameter that is being tested is the population standard deviation ( $\sigma$ ).

Step-by-step explanation:

We are given with the following null and alternative hypothesis below;

Null Hypothesis, $H_0$ : $\sigma$ = 7

Alternate Hypothesis, $H_A$ : $\sigma$ > 7

The parameter that is being tested here is the population standard deviation ( $\sigma$ ). So, the null hypothesis states that the population standard deviation is equal to 7 while on the other hand, the alternate hypothesis states that the population standard deviation is greater than 7.

The above hypothesis test is right-tailed because in the alternate hypothesis, greater than sign is there which means that if the test statistics will be more than the critical value, then the null hypothesis will be rejected.

4 0

4 years ago

Solve:

Snowcat [4.5K]

4x+11 is The answer

-2x-(-6x) two negatives make a positive so -2x-(-6x) is now -2x+6x
-2x+6x=4x

4-(-7) again two negatives make a positive so 4-(-7)
Is now 4+7
4+7=11
I hope that this was helpful if so Mark as brainliest

8 0

3 years ago

Tompkins Associates reports that the mean clear height for a Class A warehouse in the United States is 22 feet. Suppose clear he

coldgirl [10]

Given Information:

Mean clear height = μ = 22 feet

Standard deviation of clear height = σ = 4 feet

Required Information:

a) P(X > 16) = ?

b) P(X < 14) = ?

c) P(25 < X < 30) = ?

Answer:

a) P(X > 16) = 93.12%

b) P(X < 14) = 2.27%

c) P(25 < X < 30) = 20.39%

Step-by-step explanation:

What is Normal Distribution?

We are given a Normal Distribution, which is a continuous probability distribution and is symmetrical around the mean. The shape of this distribution is like a bell curve and most of the data is clustered around the mean. The area under this bell shaped curve represents the probability.

a) We want to find out the probability that the clear height is greater than 16 feet.

$P(X > 16) = 1 - P(X < 16)\\\\P(X > 16) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\P(X > 16) = 1 - P(Z < \frac{16 - 22}{4} )\\\\P(X > 16) = 1 - P(Z < \frac{-6}{4} )\\\\P(X > 16) = 1 - P(Z < -1.5)\\\\$

The z-score corresponding to -1.5 is 0.0668

$P(X > 16) = 1 - 0.0668\\\\P(X > 16) = 0.9312\\\\P(X > 16) = 93.12 \%$

Therefore, the probability that the clear height is greater than 16 feet is 93.12%

b) We want to find out the probability that the clear height is less than 14 feet

$P(X < 14) = P(Z < \frac{x - \mu}{\sigma} )\\\\P(X < 14) = P(Z < \frac{14 - 22}{4} )\\\\P(X < 14) = P(Z < \frac{-8}{4} )\\\\P(X < 14) = P(Z < -2)\\\\$

The z-score corresponding to -2 is 0.02275

$P(X < 14) = 0.02275\\\\P(X < 14) = 2.27 \%$

Therefore, the probability that the clear height is less than 14 feet is 2.27%

c) We want to find out the probability that the clear height is between 25 and 30 feet.

$P(25 < X < 30) = P( \frac{x - \mu}{\sigma} < Z < \frac{x - \mu}{\sigma} )\\\\P(25 < X < 30) = P( \frac{25 - 22}{4} < Z < \frac{30 - 22}{4} )\\\\P(25 < X < 30) = P( \frac{3}{4} < Z < \frac{8}{4} )\\\\P(25 < X < 30) = P( 0.75 < Z < 2 )\\\\$

The z-score corresponding to 0.75 is 0.7734 and 2 is 0.9773

$P(25 < X < 30) = P( Z < 2 ) - P( Z < 0.75 ) \\\\P(25 < X < 30) = 0.9773 - 0.7734 \\\\P(25 < X < 30) = 0.2039\\\\P(25 < X < 30) = 20.39 \%$

Therefore, the probability that a child spends more than 4 hours and less than 8 hours per day unsupervised is 20.39%

How to use z-table?

Step 1:

In the z-table, find the two-digit number on the left side corresponding to your z-score. (e.g 1.5, 2.2, 0.5 etc.)

Step 2:

Then look up at the top of z-table to find the remaining decimal point in the range of 0.00 to 0.09. (e.g. if you are looking for 1.50 then go for 0.00 column)

Step 3:

Finally, find the corresponding probability from the z-table at the intersection of step 1 and step 2.

6 0

3 years ago