A piecewise function f(x) is defined as shown. f(x) = StartLayout enlarged left-brace 1st Row 1st column negative five-fourths x
+ 90, 2nd column 0 less-than-or-equal-to x less-than 40 2nd row 1st column negative three-eighths x + 75, 2nd column 40 less-than-or-equal-to x less-than-or-equal-to 200 EndLayout Which table could be used to graph a piece of the function? A 2-column table has 3 rows. The first column is labeled x with entries 0, 16, 40. The second column is labeled y with entries 90, 85, 75. A 2-column table has 3 rows. The first column is labeled x with entries 0, 40, 200. The second column is labeled y with entries 90, 40, 0. A 2-column table has 3 rows. The first column is labeled x with entries 40, 120, 200. The second column is labeled y with entries 75, 30, 0. A 2-column table has 3 rows. The first column is labeled x with entries 40, 160, 200. The second column is labeled y with entries 60, 15, 0.
2 answers:
Answer:
A 2-column table has 3 rows. The first column is labeled x with entries 40, 160, 200. The second column is labeled y with entries 60, 15, 0.
Step-by-step explanation:
All of the tables have x=40 in the first column. The function value there is ...
f(x) = (-3/8)(40) +75 = -15 +75 = 60
Only the last table has y = 60 for x = 40.
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A check of the other points in that table shows they are all on the same (second) piece of the graph, as required by the problem statement. Those points are marked with a purple x in the attachment.
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The volume of the planter that measures 60 l, 60 w. 60 h (D) 216000 cm³
<u>Explanation:</u>
Length, l = 60 cm
Width, w = 60 cm
Height, h = 60 cm
Volume, v = ?
We know,
Volume = length ×width × height
Substitute the values in the formula.
Therefore, the volume of the planter is 216,000 cm³