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The answer is A I believe
Given
Rob is twice Joshua's age
Nick is 5 years older than Joshua.
sum of all their ages is 45.
Find the age of nick.
To proof
As given
Rob is twice Joshua's age
let Joshua's age = x
than Rob age = 2x
Nick is 5 years older than Joshua.
Nick age = 5 + x
sum of all their ages is 45
than the equation becomes
Joshua's age + Rob age + Nick age = 45
put the value
x + 2x + 5 + x = 45
4x = 40
x = 10
Joshua's age = 10 year
than Rob age = 20 year
Nick age = 5 + 10
= 15year
Hence proved
Answer:
6 years
Step-by-step explanation:
So each person's age can be represented as a linear equation, since each year our age increases by 1. It can be represented in the slope-intercept form: y=mx+b. The slope in this case is going to be 1, since the time is going to be years, and each year everyone's age goes up by 1 (of course if you're still alive...) and y-intercept in this case represents their current age.
So the father can be represented as: y=x+38
The sons can be represented as: y = x+13 and y=x+5
The daughter can be represented as: y=x+8
So adding up all his children you get:
(x+13)+(x+5)+(x+8)
This gives you the equation:
3x+26
Now set this equal to the father's age to solve for x (in this context it's years)
3x+26=x+38
Subtract from both sides
2x+26=38
Subtract 26 from both sides
2x=12
Divide both sides by 2
x=6
So in 6 years the father will be the same age as his children put together
Answer:
The slope is 2/3 and the y intercept is 5/9
Step-by-step explanation:
This is written in the form
y= mx+b where m is the slope and b is the y intercept
y = 2/3x +5/9
m = 2/3 and b=5/9
The slope is 2/3 and the y intercept is 5/9