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Vanyuwa [196]
3 years ago
5

In the diagram below, P is circumscribed about quadrilateral ABCD. What is the value of x?

Mathematics
2 answers:
alexira [117]3 years ago
7 0
We know that
In any quadrilateral where the vertices are on the circumference of a circle, the opposite angles add up to 180 degrees. 

So,
 in this problem
(x+20) + 110 = 180 \\ x+130=180 \\ x=180-130 \\ x=50degrees

therefore

the answer is
x=50degrees
nlexa [21]3 years ago
3 0
When a quadrilateral is inscriptible the opposite angles are supplementary       
So:   A + C = 180°
X + 20° + 110° = 180°
Then:   
                X = 50°
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ArbitrLikvidat [17]
1568/23 = 68 4/23 <====
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2 years ago
The probability that an event will occur is 95%. Which of these best describes the likelihood of the event occurring?
AfilCa [17]

Answer:

Likely

First option is correct.

Step-by-step explanation:

The probability for occurring the event = 95% = 0.95

Let us understand different types of events:-

  • Certain events: If the probability of occurring an even is 1, then it is a certain event.
  • Impossible events: If the probability of occurring an even is 0, then it is a impossible event.
  • Likely events: If the probability of occurring an even is close to 1, then it is a likely event.
  • Unlikely events: If the probability of occurring an even is close to 0, then it is a unlikely event.

Now, the probability for occurring the event = 95% = 0.95, which is close to 1.

Hence, we can conclude that the event is likely.

First option is correct.

4 0
3 years ago
Read 2 more answers
Rewrite 128 in an expomential notion using 2 as a base
KiRa [710]
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3 0
2 years ago
Perform a first derivative test on the function ​f(x)equals2 x cubed plus 3 x squared minus 120 x plus 6​; ​[minus5​,8​]. Bold
maria [59]

Answer:

a) Critical points

x = 4 and x = -5

b) x = 4 corresponds to a minimum point for the function f(x)

x = - 5 corresponds to a maximum point for the function f(x)

c) The minimum value of f(x) in the interval = -298

The maximum value of f(x) in the interval = 431;

Step-by-step explanation:

f(x) = 2x³ + 3x² - 120x + 6 in the interval [-5, 8]

a) To obtain the critical points, we need to obtain the first derivative of the function with respect to x. Because at critical points of a function, f(x), (df/dx) = 0

f'(x) = (df/dx) = 6x² + 6x - 120 = 0

6x² + 6x - 120 = 0

Solving the quadratic equation,

x = 4 or x = -5

The two critical points, x = 4 and x = -5 are in the interval given [-5, 8] (the interval includes -5 and 8, because it's a closed interval)

b) To investigate the nature of the critical points, we obtain f"(x)

Because f'(x) changes sign at the critical points

If f"(x) > 0, then it's a minimum point and if f"(x) < 0 at c, then it's a maximum point.

f"(x) = (d²f/dx²) = 12x + 6

at critical point x = 4

f"(x) = 12x + 6 = 12(4) + 6 = 54 > 0, hence, x = 4 corresponds to a minimum point.

at critical point x = -5

f"(x) = 12x + 4 = 12(-5) + 4 = -56 < 0, hence, x = -5 corresponds to a maximum point.

c) At x = 4,

f(x) = 2x³ + 3x² - 120x + 6 = 2(4)³ + 3(4)² - 120(4) + 6 = -298

At x = - 5

f(x) = 2x³ + 3x² - 120x + 6 = 2(-5)³ + 3(-5)² - 120(-5) + 6 = 431

7 0
2 years ago
PLEASE HELP ASAP!!!!!!!!!
Butoxors [25]

Answer:

it’s the last one

8 0
2 years ago
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