All categories

2 years ago

What is the best first step in solving the equation below.

Mathematics

2 answers:

REY [17]2 years ago

8 0

Good evening ,

______

Answer:

Subtract 3x on both sides

___________________

Step-by-step explanation:

3x−5=7x+11 ⇔ (-3x)+3x−5=+(-3x)+7x+11 ⇔ −5=4x+11 ⇔ -16=4x ⇔ -4=x.

mars1129 [50]2 years ago

7 0

Answer:

<h2>Subtract 3x from both sides</h2>

Step-by-step explanation:

3x - 5 = 7x + 11

Firs step:

add 5 to both sides: 3x - 5 + 5 = 7x + 11 + 5 → 3x = 7x + 16

subtract 7x from both sides: 3x - 7x - 5 = 7x - 7x + 11 → -2x - 5 = 11

subtract 3x from both sides: 3x - 3x - 5 = 7x - 3x + 11 → -5 = 4x + 11

subtract 11 from both sides: 3x - 5 - 11 = 7x + 11 - 11 → 3x - 16 = 7x

If you want solution.

3x - 5 = 7x + 11 <em> subtract 3x from both sides</em>

3x - 3x - 5 = 7x - 3x + 11

-5 = 4x + 11 <em>subtract 11 from both sides</em>

-5 - 11 = 4x + 11 - 11

-16 = 4x <em>divide both sides by 4</em>

-16/4 = 4x/4

-4 = x → x = -4

You might be interested in

Determine if x+3 is a factor of -3x^3+6x^2+6x+9. How do u know

krek1111 [17]

By the factor theorem, if x + 3 is a factor of f(x) = -3x^3 + 6x^2 + 6x + 9, then f(-3) = 0
f(-3) = -3(-3)^3 + 6(-3)^2 + 6(-3) + 9 = -3(-27) + 6(9) - 18 + 9 = 81 + 54 - 9 = 126.

Therefore, x + 3 is not a factor of the given function

6 0

2 years ago

The average hourly wage of workers at a fast food restaurant is $6.75 with a standard deviation of $0.25. If the distribution is

Sholpan [36]

Answer:

25% would be the answer

Step-by-step explanation:

3 0

3 years ago

Write an expression for each quantity

Ira Lisetskai [31]

28) 7w
30) x/16
32) I/12

4 0

3 years ago

Heather is collecting beanbag animals. she started her collection with six beanbag animals just eight weeks ago. during each of

Natali5045456 [20]

22

Starts with 6

Adds 2 for 8 weeks (2*8 = 16)
16 + 6 = 22

8 0

2 years ago

A computer program contains one error. In order to find the error, we split the program into 6 blocks and test two of them, sele

Aleksandr-060686 [28]

There are $\dbinom62$ ways of selecting two of the six blocks at random. The probability that one of them contains an error is

$\dfrac{\dbinom11\dbinom51}{\dbinom62}=\dfrac5{15}=\dfrac13$

So $X$ has probability mass function

$f_X(x)=\begin{cases}\dfrac13&\text{for }x=1\\\\\dfrac23&\text{for }x=0\end{cases}$

These are the only two cases since there is only one error known to exist in the code; any two blocks of code chosen at random must either contain the error or not.

The expected value of finding an error is then

$\displaystyle\sum_{x=0}^1xf_X(x)=0\times\dfrac23+1\times\dfrac13=\dfrac13$

7 0

2 years ago